From the rate expression for the following reactions, determine their order of renction and the dimensions of the rate constants. (u) \(\mathrm{WNO}_{(\mathrm{k})} \cdots \mathrm{N}_{2} \mathrm{O}_{(\mathrm{g})}+\mathrm{NO}_{2(\mathrm{~g})} ; \quad\) Rate \(=K[\mathrm{NO}]^{2}\) Rate \(=K\left[\mathrm{H}_{2} \mathrm{O}_{2}\right][\mathrm{I}]\) (c) \(\mathrm{CH}_{3} \mathrm{CHO}_{(\mathrm{g})} \longrightarrow \mathrm{CH}_{4(\mathrm{~g})}+\mathrm{CO}_{(\mathrm{g})} ;\) Rate \(=K\left[\mathrm{CH}_{3} \mathrm{CHO}\right]^{3 / 2}\) (d) \(\mathrm{CHCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(g)} \longrightarrow \mathrm{CCl}_{4(\mathrm{~g})}+\mathrm{HCl}_{(\mathrm{g})}\) Rate \(=K\left[\mathrm{CHCl}_{3}\right]\left[\mathrm{Cl}_{2}\right]^{1 / 2}\)

Short Answer

Expert verified
For reaction (u) and (v), the reaction order is 2 with rate constant units M^(-1)*s^(-1); for reactions (c) and (d), the reaction order is 3/2 with rate constant units M^(-1/2)*s^(-1)

Step by step solution

01

Determining the Reaction Order for Reaction (u)

For reaction (u), the rate is given by Rate = K[NO]^2. The reaction order is determined by adding the exponents of the concentration terms in the rate expression. In this case, the sum of exponents is 2, thus it is a second-order reaction.
02

Determining the Units of Rate Constant for Reaction (u)

The rate of a reaction is given in units of concentration per time, usually M/s (Molarity per second). For a second-order reaction, the rate constant K has units of M^(-1)*s^(-1). This is determined by the formula Rate = K[A]^n and dimensional analysis where [A] has units of M and Rate has units of M/s.
03

Determining the Reaction Order for Reaction (v)

For reaction (v), the rate is given as Rate = K[H2O2][I]. The reaction order is determined by adding the exponents of the concentration terms, which are both 1 for this reaction. The total order is therefore 2, indicating a second-order reaction.
04

Determining the Units of Rate Constant for Reaction (v)

The units of K for a second-order overall reaction are M^(-1)*s^(-1), obtained by the same dimensional analysis as the first reaction.
05

Determining the Reaction Order for Reaction (c)

For reaction (c), the rate expression is Rate = K[CH3CHO]^(3/2). The reaction order is 3/2 by adding the exponent of the concentration term, indicating a reaction order of 3/2.
06

Determining the Units of Rate Constant for Reaction (c)

The units of the rate constant K for a reaction order of 3/2 are M^(-1/2)*s^(-1), which is derived from ensuring the rate expression has consistent units of M/s.
07

Determining the Reaction Order for Reaction (d)

For reaction (d), the rate is given by Rate = K[CHCl3][Cl2]^(1/2). The reaction order is 1 + 1/2 = 3/2, thus it is a 3/2-order reaction.
08

Determining the Units of Rate Constant for Reaction (d)

The rate constant K has units of M^(-1/2)*s^(-1) for a reaction order of 3/2, as determined by the general approach of matching the rate expression units with M/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Order
The reaction order indicates the relationship between the reactant concentrations and the rate at which the reaction occurs. It sums up the exponents of the concentration terms in the rate equation. Understanding the reaction order of a chemical process is fundamental as it determines how the reaction rate changes when concentrations of reactants vary.

For example, if a rate equation is written as Rate = K[A]2, where K is the rate constant and [A] is the concentration of reactant A, the reaction is second-order with respect to A. This means that if the concentration of A doubles, the rate of the reaction will increase by a factor of four, as the concentration term is squared in the rate equation. Reaction order can be integers, like 2 in the aforementioned example, or fractions, such as 3/2, as seen in reaction (c) and (d) from our exercise.
Rate Constant Dimensions
The dimensions or units of the rate constant (K) give us crucial information about the rate and order of a reaction. For a simple reaction where rate = K[A]n, the units of K can be determined through dimensional analysis by balancing the units of rate (usually M/s or mol/L·s) with the units derived from the concentration of reactants raised to the power of the reaction order.

In our exercise examples, for a second-order reaction (u) and (v), K has the units of M-1·s-1. For the reaction with order 3/2 (c) and (d), the units of K are M-1/2·s-1. This dimensional analysis is essential for consistency and helps us validate our experimental results and theoretical predictions.
Second-Order Reaction
A second-order reaction is characterized by a rate that is proportional to the square of the concentration of one reactant, or directly proportional to the product of the concentrations of two reactants. Looking at the initial step-by-step solution, reactions (u) and (v) are examples of second-order reactions.

In terms of kinetics, these reactions can be described by rate laws such as Rate = K[A]2 or Rate = K[A][B]. The integrated rate law for a second-order reaction will yield a graph of 1/[A] versus time that is a straight line, indicating that the reaction follows second-order kinetics. This is significant in predicting how long a reaction will take and how the concentration of reactants will change over that period.
Rate Determining Step
The rate determining step is the slowest step in a reaction mechanism that dictates the overall rate of the chemical reaction. It’s analogous to the narrowest point in an hourglass where the rate of sand falling is governed by the smallest opening. In a multi-step reaction, once the rate determining step is completed, the remainder of the process typically proceeds much faster.

Understanding the rate determining step is crucial for both theoretical studies and practical applications, such as in the design of catalysts and optimization of industrial processes. Identifying this bottleneck step enables chemists to modify reaction conditions or use catalysts to accelerate the overall reaction by lowering the activation energy of the rate determining step, thus increasing the reaction rate.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free