Thermal decomposition of a compound is of first order. If \(50 \%\) sample of the compound is decomposed in 120 minute, how long will it take for \(90 \%\) of the compound to decompose?

Short Answer

Expert verified
To find the time for 90% decomposition using the calculated rate constant, solve \( ln(10) = \frac{ln(2)}{120}t \) to get \(t = 120 \times \frac{ln(10)}{ln(2)}\) minutes.

Step by step solution

01

Understanding First-Order Decomposition

First-order reactions have a rate proportional to the concentration of one reactant. The equation describing first-order kinetics is \begin{align*} ln\frac{[A]_0}{[A]} &= kt \end{align*}where \begin{itemize} \item \([A]_0\) is the initial concentration, \item \([A]\) is the concentration at time \(t\), \item \(k\) is the rate constant, and \item \(t\) is the time.\end{itemize}
02

Determining the Rate Constant (k)

Given that 50% of the sample decomposes in 120 minutes, we can write the equation for the half-life of the reaction as:\begin{align*} ln\frac{[A]_0}{[A]_0/2} &= kt \end{align*}Since \begin{align*} ln(2) &= kt_{1/2} \end{align*}we find \begin{align*} k &= \frac{ln(2)}{t_{1/2}} \end{align*}By substituting the given half-life time \(t_{1/2} = 120\) minutes, we can calculate the rate constant \(k\).
03

Calculating the Time for 90% Decomposition

For 90% decomposition, only 10% of the reactant remains. Therefore, \begin{align*} [A] &= 0.10[A]_0 \end{align*}Now we can substitute the calculated \(k\) and solve the first-order rate law for \(t\) to find the time needed for 90% decomposition:\begin{align*} ln\frac{[A]_0}{0.10[A]_0} &= kt \end{align*}Rewrite the equation to solve for \(t\) and substitute the value of \(k\).
04

Solution for Decomposition Time

Solving the natural logarithm equation \begin{align*} ln(10) &= kt \end{align*}and using the previously found \(k\) value, we get the time \(t\) required for 90% decomposition.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the study of the rates of chemical processes, the factors that affect these rates, and the mechanisms by which reactions occur. Understanding kinetics is key to predicting the behavior of chemicals over time and can help in designing reactions for industrial, laboratory, and everyday applications.

For instance, in the exercise, we're examining a first-order reaction, which means the reaction rate is directly proportional to the concentration of the reactant. Hence, as the reactant concentration decreases, so does the rate of reaction. This relationship is described mathematically through rate equations, which allow us to determine the time required for a certain percentage of reactant to decompose. By studying kinetics, we not only understand the speed at which a product is formed but also gain valuable insights into the reaction mechanism itself.
Reaction Rate Constant
The reaction rate constant, represented by the symbol 'k,' is a crucial number in chemical kinetics that describes the speed of a chemical reaction. For a first-order reaction, the rate constant provides the link between the concentration of the reactants and the rate at which they are consumed.

This constant is determined experimentally and varies with temperature, as depicted by the Arrhenius equation. In the given exercise, once the half-life for a decomposing sample is known, we can calculate the rate constant, which then can be utilized to find out how long it will take for a different percentage of the compound to decompose. Importantly, 'k' remains the same regardless of concentration, which underpins the predictability of reaction outcomes under constant conditions.
Half-Life of Reaction
The half-life of a reaction, often denoted as 't_{1/2}', is the time required for half of the reactant to be used up in a chemical reaction. For first-order reactions, the half-life is constant because it does not depend on the reactant's initial concentration.

In the context of our problem, knowing that the half-life of the reaction is 120 minutes allows us to calculate the rate constant 'k.' This value can then be used to determine the time it will take for 90% of the sample to decompose, simply by applying the first-order reaction equation. The concept of half-life is not only essential in chemical kinetics but also in various fields such as pharmacology, radioactive dating, and environmental science, highlighting its universal significance.

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Most popular questions from this chapter

The reaction; \(2 A+B+C \longrightarrow D+2 E ;\) is found to be I order in \(A\), II order in \(B\) and zero order in \(C\). (a) Write the rate expression. (b) What is the effect on rate on increasing the conc. of \(A, B\) and \(C\) two times?

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