Chapter 10: Problem 141
Acetyl bromide reacts with excess of \(\mathrm{CH}_{3} \mathrm{MgI}\) followed by treatment with a saturated solution of \(\mathrm{NH}_{4} \mathrm{Cl}\) gives (a) Acetone (b) Acetamide (c) 2 -methyl-2-propanol (d) Acetyl iodide
Short Answer
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Key Concepts
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