Chapter 11: Problem 108
Oxymercuration-demercuration reaction of 1 -methylcyclohexene gives (a) Trans-2-methyl cyclohexanol (b) Cis-2-methylcyclohexanol (c) 1-methylcyclohexanol (d) Mixture of cis-and trans-2-methylcyclohexanol
Short Answer
Expert verified
The product of the oxymercuration-demercuration reaction of 1-methylcyclohexene is (a) Trans-2-methyl cyclohexanol.
Step by step solution
01
Understanding Oxymercuration-Demercuration
The oxymercuration-demercuration reaction is a hydration process where an alkene is converted to an alcohol. The reaction proceeds with Markovnikov addition, where the hydroxyl group (OH) attaches to the more substituted carbon atom. First, the alkene reacts with mercuric acetate in an aqueous solution to form an organomercurial alcohol intermediate.
02
Predicting the Intermediate
1-methylcyclohexene will react with the mercury compound to form an intermediate mercurinium ion where mercury will add to the more substituted carbon due to Markovnikov's rule. Since the reaction forms a three-membered ring, both carbons are secondary, but the positive charge will be on the less substituted carbon which does not bear the methyl group.
03
Addition of Water
Water attacks the more positively charged carbon in the mercurinium ion, leading to the formation of an organomercurial alcohol intermediate. This attack occurs from the more sterically accessible side, which is typically the less hindered face of the molecule, resulting in the trans addition of Hg-OAc and OH with respect to the double bond in the alkene.
04
Demercuration
In the demercuration step, the organomercurial intermediate is treated with a reducing agent, such as sodium borohydride (NaBH4), to replace the mercury atom with a hydrogen atom. The stereochemistry of the addition is retained in this step, leading to the formation of the alcohol product.
05
Determining the Final Product
The final product retains the stereochemistry generated during the previous steps; specifically, the hydroxyl group will be on the opposite side of the cyclohexane ring compared to the methyl group that was already present on the starting alkene. Hence, the final product is trans-2-methylcyclohexanol.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Markovnikov's Rule
Understanding the pathway of chemical reactions involving alkenes, particularly when it comes to product prediction, can often be navigated via Markovnikov's rule. This rule states that during the addition of a protic acid (HX) to an asymmetrical alkene, the hydrogen atom (H) will bind to the carbon with the greater number of hydrogen atoms, and the other part of the acid (X) will bind to the carbon with fewer hydrogen atoms, which is typically the more substituted carbon.
This concept is vital when analyzing the oxymercuration-demercuration reaction. In this process, the hydroxyl group (OH) binds to the more substituted carbon atom of the alkene. It's a fascinating rule because it showcases the inherent stability of carbocations—the more alkyl groups attached to the carbocation, the more stable it is. This stability guides the reaction toward the creation of the more stable intermediate and ultimately, influences the formation of the major product.
This concept is vital when analyzing the oxymercuration-demercuration reaction. In this process, the hydroxyl group (OH) binds to the more substituted carbon atom of the alkene. It's a fascinating rule because it showcases the inherent stability of carbocations—the more alkyl groups attached to the carbocation, the more stable it is. This stability guides the reaction toward the creation of the more stable intermediate and ultimately, influences the formation of the major product.
Real-World Application
Markovnikov's rule isn't merely an academic notion; it's essential in synthetic chemistry for creating specific molecules. By predicting where the functional group will attach, chemists can design routes to synthesize compounds with desired properties for various applications, including pharmaceuticals and materials science.Alkene Hydration
Alkene hydration is a fundamental chemical reaction where a water molecule (H2O) is added across the double bond of an alkene, resulting in an alcohol. This reaction is particularly important because it transforms hydrophobic olefins into hydrophilic alcohols, significantly altering the solubility and reactivity of the compounds.
The mechanism typically goes through an electrophilic addition pathway in which the alkene acts as a nucleophile and attacks an electrophilic species that bears a good leaving group. In the context of our exercise, the oxymercuration step represents the first phase of alkene hydration, where an organomercurial alcohol intermediate is formed.
The mechanism typically goes through an electrophilic addition pathway in which the alkene acts as a nucleophile and attacks an electrophilic species that bears a good leaving group. In the context of our exercise, the oxymercuration step represents the first phase of alkene hydration, where an organomercurial alcohol intermediate is formed.
Benefits in Synthesis
Why is hydration important? Besides increasing the molecule's functionality, it's a crucial step in transforming petrochemical feedstocks into valuable chemicals and intermediates, including alcohols that serve as solvents, precursors to plasticizers, or even biofuel components. The hydration reaction, in its various forms, provides an array of pathways to create complex molecules with broad utility in industry.Stereochemistry
Stereochemistry refers to the three-dimensional arrangement of atoms within molecules and the impact of this arrangement on chemical and physical properties. It's a central topic in organic chemistry, especially when discussing mechanisms and product configurations, as seen in our oxymercuration-demercuration practice problem.
In the given solution, the stereochemistry is key in determining the final alcohol product's configuration. When the intermediate organomercurial alcohol is formed, it adopts a specific stereochemistry, where the hydroxyl group is added on the opposite side of the existing substituent on the cyclohexene ring. This 'anti' addition means the final product has trans stereochemistry.
In the given solution, the stereochemistry is key in determining the final alcohol product's configuration. When the intermediate organomercurial alcohol is formed, it adopts a specific stereochemistry, where the hydroxyl group is added on the opposite side of the existing substituent on the cyclohexene ring. This 'anti' addition means the final product has trans stereochemistry.