Chapter 11: Problem 139
The major product of the following reaction is \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}=\mathrm{CHCH}_{3} \frac{\text { (i) } \mathrm{Hg}(\mathrm{OAc})_{2} \mathrm{THF}=\mathrm{H}_{2} \mathrm{O}}{\text { (ii) } \mathrm{NaBH}_{4}}\)
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