Chapter 12: Problem 47
The compound that will not give iodoform on treatment with alkali and iodine is (a) Acetone (b) Ethanol (c) Diethyl ketone (d) Isopropyl alcohol
Short Answer
Expert verified
Diethyl ketone (option c) is the compound that will not give iodoform on treatment with alkali and iodine.
Step by step solution
01
Understanding the Iodoform Test Requirements
The iodoform test is used to identify compounds with a methyl ketone group (-COCH3) or ethanol. The test gives a positive result if the compound has a methyl group directly bonded to the carbonyl carbon (as in methyl ketones) or is ethanol. The presence of these groups leads to the formation of yellow precipitate of iodoform, CHI3.
02
Evaluating Option (a) - Acetone
Acetone (CH3COCH3) has a methyl ketone structure and is expected to give a positive iodoform test. Therefore, acetone will give iodoform on treatment with alkali and iodine.
03
Evaluating Option (b) - Ethanol
Ethanol (CH3CH2OH) also responds to the iodoform test and will give yellow precipitate of iodoform when treated with alkali and iodine.
04
Evaluating Option (c) - Diethyl ketone
Diethyl ketone (CH3CH2COCH2CH3) does not have a methyl group directly bonded to the carbonyl carbon. Therefore, it will not respond to the iodoform test, not giving a yellow precipitate of iodoform.
05
Evaluating Option (d) - Isopropyl alcohol
Isopropyl alcohol (CH3CH(OH)CH3) can be oxidized to acetone, which has a methyl ketone group. Therefore, isopropyl alcohol gives a positive iodoform test when oxidized to acetone and then treated with alkali and iodine.
06
Identifying the Compound That Will Not Give Iodoform
Comparing all the options based on their chemical structure, diethyl ketone (option c) is the compound that will not give the iodoform on treatment with alkali and iodine because it lacks the necessary methyl ketone structure or alcohol group that reacts in the test.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Methyl Ketone Group
The methyl ketone group is a functional group characterized by a carbonyl group (C=O) with a methyl group (CH3) on one side. This structure is denoted as -COCH3. It's a crucial feature in organic chemistry as it participates in several reactions, one of which is the iodoform test.
In the context of the iodoform test, compounds featuring the methyl ketone group can be identified by the formation of a yellow precipitate of iodoform (CHI3) when treated with iodine in the presence of an alkali. It's a classic test to identify whether a compound contains the methyl ketone group, which is often a part of organic molecule identification in laboratory settings.
In the context of the iodoform test, compounds featuring the methyl ketone group can be identified by the formation of a yellow precipitate of iodoform (CHI3) when treated with iodine in the presence of an alkali. It's a classic test to identify whether a compound contains the methyl ketone group, which is often a part of organic molecule identification in laboratory settings.
Chemical Structure Analysis
Chemical structure analysis plays a pivotal role in understanding how different compounds will react in certain situations. It involves examining how atoms are arranged in a molecule and how they are connected, including the identification of functional groups such as the methyl ketone group.
In the iodoform test, analyzing the structure is essential to predict whether the compound will produce iodoform. For example, acetone with the structure CH3COCH3 has a methyl group attached to a carbonyl carbon, making it reactive in the test. Conversely, diethyl ketone (CH3CH2COCH2CH3) lacks this specific structure and will not give the same result. The analysis of these structures is not only important for laboratory tests but also to provide a deeper understanding of the reactivity and properties of organic compounds.
In the iodoform test, analyzing the structure is essential to predict whether the compound will produce iodoform. For example, acetone with the structure CH3COCH3 has a methyl group attached to a carbonyl carbon, making it reactive in the test. Conversely, diethyl ketone (CH3CH2COCH2CH3) lacks this specific structure and will not give the same result. The analysis of these structures is not only important for laboratory tests but also to provide a deeper understanding of the reactivity and properties of organic compounds.
NEET Chemistry Preparation
Preparing for NEET Chemistry requires an in-depth understanding of various chemical reactions and processes, including the iodoform test. It's vital for students to grasp concepts such as the methyl ketone group and the methodology behind chemical structure analysis, as they are frequently tested in this competitive exam.
A thorough preparation typically involves mastering these topics, solving numerous practice problems, and familiarizing oneself with laboratory procedures like the iodoform test. For NEET aspirants, understanding the iodoform test is not only about remembering the conditions that lead to a positive result but also the underlying chemical principles and reasoning that explain why certain compounds react while others do not.
A thorough preparation typically involves mastering these topics, solving numerous practice problems, and familiarizing oneself with laboratory procedures like the iodoform test. For NEET aspirants, understanding the iodoform test is not only about remembering the conditions that lead to a positive result but also the underlying chemical principles and reasoning that explain why certain compounds react while others do not.