Which of the following concentration factor is affected by change in temperature? (a) Molarity (b) Molality (c) Mole fraction (d) Weight fraction

Short Answer

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Molarity is affected by changes in temperature.

Step by step solution

01

Understanding Concentration Terms

First, it's important to understand what each term means. Molarity (M) is the number of moles of solute per liter of solution. Molality (m) is the number of moles of solute per kilogram of solvent. Mole fraction is the ratio of the number of moles of a component to the total number of moles of all components in the mixture. Weight fraction is the ratio of the mass of one component to the total mass of the mixture.
02

Considering Temperature Dependence

Next, consider how temperature might affect each of these concentration measures. Molarity is dependent on volume, which can change with temperature due to thermal expansion or contraction. Molality is unaffected by temperature as it is a ratio of moles of solute to mass of solvent and mass is not affected by temperature. Mole fraction and weight fraction are also independent of temperature because they are ratios that do not involve volume.
03

Identifying the Temperature-affected Concentration Factor

Based on the above considerations, only molarity is affected by changes in temperature because it involves volume, which can vary with temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity
Molarity is a fundamental concept in chemistry that helps us describe the concentration of a solution. It is defined as the number of moles of solute present in one liter of solution. Mathematically, it can be expressed using the formula:
\[ Molarity (M) = \frac{moles \, of \, solute}{liters \, of \, solution} \]
Molarity is temperature-dependent because the volume of a solution can change with the temperature due to thermal expansion or contraction. As temperature increases, the volume of a liquid tends to increase, which may result in a lower concentration of the solute if the number of moles remains constant. This is important to consider in chemical reactions where consistent molarity is required. For practical applications, chemists often measure and report concentrations at a standard temperature to maintain consistency.
Molality
Molality is another way to express the concentration of a solution, especially useful when temperature fluctuates. It is defined as the number of moles of solute per kilogram of the solvent. Unlike molarity, molality does not change with temperature because it is based on mass, which is not affected by temperature changes. The formula for molality is given by:
\[ Molality (m) = \frac{moles \, of \, solute}{kilograms \, of \, solvent} \]
Due to its temperature independence, molality is particularly valuable for studying properties of solutions under varying thermal conditions, such as in boiling point elevation and freezing point depression experiments.
Mole Fraction
The mole fraction is a dimensionless quantity representing the ratio of the number of moles of one component to the total number of moles of all components in the mixture. It provides a way to express the concentration of a constituent in a mixture without using units. The mole fraction, represented by \( \chi \), is calculated as follows:
\[ Mole \ Fraction (\chi) = \frac{moles \, of \, component}{total \, moles \, of \, all \, components} \]
Because the mole fraction is a ratio, it remains unaffected by temperature changes. Such constancy makes mole fraction ideal for applications that involve different phases of matter or those that operate over a wide range of temperatures, such as gas mixtures.
Temperature Dependence of Concentration
Understanding the temperature dependence of various concentration terms is vital when working with chemical solutions. As established, molarity is susceptible to temperature changes because it is dependent on the volume, which can expand or contract with the temperature fluctuations. Conversely, molality and mole fraction are not influenced by temperature as they are ratios that are independent of volume.
This distinction is crucial when choosing the right concentration measure for an experiment or industrial process. For example, in endothermic and exothermic reactions where heat is absorbed or released, choosing a temperature-independent concentration like molality or mole fraction is advantageous for maintaining accurate and consistent readings despite the thermal changes occurring during the reaction.

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Most popular questions from this chapter

Which one of the following statements is false? (a) Two sucrose solutions of same molality prepared in different solvents will have the same freezing point depression (b) The osmotic pressure (\pi) of a solution is given by the equation \(\pi=M R T\), where \(M\) is the molarity of the solution (c) Raoult's law states that the vapour pressure of a component over a solution is proportional to its mole fraction (d) The correct order of osmotic pressure for \(0.01 \mathrm{M}\) aqueous solution of each compound is \(\mathrm{BaCl}_{2}>\) \(\mathrm{KCl}>\mathrm{CH}_{3} \mathrm{COOH}>\) Sucrose

\(3.65 \mathrm{~g}\) of \(\mathrm{HCl}\) is dissolved in \(16.2 \mathrm{~g}\) of water The mole fraction of \(\mathrm{HCl}\) in the resulting solution is: (a) \(0.4\) (b) \(0.3\) (c) \(0.2\) (d) \(0.1\)

Osmotic pressure observed when benzoic acid is dissolved in benzene is less than that expected from theoretical considerations. This is because:(a) Benzoic acid is an organic solute (b) Benzoic acid has higher molar mass than benzene (c) Benzoic acid gets associated in benzene (d) Benzoic acid gets dissociated in benzene

If \(0.44 \mathrm{~g}\) of substance dissolved in \(22.2 \mathrm{~g}\) of benzene lowers the freezing point of benzene by \(0.567^{\circ} \mathrm{C}\), then the molecular mass of substance is, (the molal depression constant \(\left.=5.12^{\circ} \mathrm{C} \mathrm{mol}^{-1} \mathrm{~kg}\right)\) (a) \(128.4\) (b) \(156.6\) (c) \(178.9\) (d) \(232.4\)

A decimolar solution of potassium ferrocyanide is \(50 \%\) dissociated at \(300 \mathrm{~K}\). Calculate the osmotic pressure of the solution. \(\left(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)\) (a) \(0.07389 \mathrm{~atm}\) (b) \(7.389 \mathrm{~atm}\) (c) \(738.89 \mathrm{~atm}\) (d) \(73.89 \mathrm{~atm}\)

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