Chapter 3: Problem 147
For the redox reaction \(\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(0.1 \mathrm{M}) \longrightarrow \mathrm{Zn}^{2+}(1 \mathrm{M})+\mathrm{Cu}(\mathrm{s})\) Taking place in a cell, \(\mathrm{E}_{\text {cell }}^{\circ}\) is \(1.10\) volt. \(\mathrm{E}_{\text {cell }}\) for the cell will be ( \(2.303 \mathrm{RT} / F=0.0591\) ): (a) \(2.14 \mathrm{~V}\) (b) \(1.80 \mathrm{~V}\) (c) \(1.07 \mathrm{~V}\) (d) \(0.82 \mathrm{~V}\)
Short Answer
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