Chapter 3: Problem 23
A metal ion \(\mathrm{M}^{3+}\) loses three electrons to produce another cation. The oxidation number of the metal in the cation is: (a) \(+3\) (b) \(+4\) (c) \(-3\) (d) \(+6\)
Short Answer
Expert verified
The oxidation number of the metal ion in the cation is +3.
Step by step solution
01
Understanding the Process
When a metal ion loses electrons, it is undergoing oxidation, and its oxidation number increases. The number of electrons lost dictates the increase in the oxidation number.
02
Identifying Electron Loss
The metal ion \(\mathrm{M}^{3+}\) is stated to lose three electrons. This means that the initial charge of +3 will increase by 3.
03
Calculating the New Oxidation Number
Since the metal ion loses three electrons, its oxidation number will increase by 3 units. Therefore, the new oxidation number is \(+3 + 3 = +6\). However, this does not match any of the given answers, suggesting there might be an error in the question or a misunderstanding.
04
Re-evaluating the Oxidation Number
Since the charge of the ion is already \(+3\) and it loses three electrons, the correct interpretation should not involve addition. Instead, it should be recognized that the \(\mathrm{M}^{3+}\) notation indicates that the ion already has an oxidation state of +3. Losing three electrons won't change this oxidation state; it simply means it is now a neutral atom, but that is not what's asked. We are asked to report the oxidation state of the cation, not the resulting atom.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Redox Reactions
Redox reactions, short for reduction-oxidation reactions, are chemical processes that involve the transfer of electrons between two substances. In these reactions, one substance undergoes oxidation by losing electrons, and another substance undergoes reduction by gaining electrons.
Understanding redox reactions is essential because they play a vital role in various biological processes, industrial applications, and even in everyday life like in batteries. Oxidation and reduction always occur simultaneously because electrons are transferred from the oxidizing agent to the reducing agent, which connects the two processes in what is known as a redox couple.
Understanding redox reactions is essential because they play a vital role in various biological processes, industrial applications, and even in everyday life like in batteries. Oxidation and reduction always occur simultaneously because electrons are transferred from the oxidizing agent to the reducing agent, which connects the two processes in what is known as a redox couple.
The Role of Electron Transfer
Electrons are the currency of chemical reactions and in redox reactions, they are moved from one atom or molecule to another. The loss or gain of these electrons alters the overall charge of the substances involved, leading to changes in their chemical properties and behaviors.Identifying Oxidation and Reduction
In order to identify which species is oxidized and which is reduced, one must track the movement of electrons. A species that loses electrons is said to be oxidized, while the one that gains electrons is reduced.Chemical Oxidation
Chemical oxidation refers to the process where a substance loses electrons and increases its oxidation state. This can involve the interaction with oxygen, hence the name 'oxidation', but it isn't limited to it; any electron loss, regardless of the electron acceptor, is considered oxidation.
Oxidation can be part of a redox reaction or it can occur on its own in a process called disproportionation. Disproportionation is a type of redox reaction where a single substance undergoes both oxidation and reduction, transforming into two different products.
Oxidation can be part of a redox reaction or it can occur on its own in a process called disproportionation. Disproportionation is a type of redox reaction where a single substance undergoes both oxidation and reduction, transforming into two different products.
Examples of Oxidation
Common examples of oxidation include the rusting of iron, the browning of fruit, and the burning of fuels. In each of these examples, oxidation causes significant changes in the chemical composition and properties of the substance.Oxidation State Calculation
The oxidation state, or oxidation number, indicates the degree of oxidation of an atom in a compound or ion based on the hypothetical charge it would have if all bonds were considered ionic. Calculating oxidation states is a fundamental skill in chemistry that helps us understand the electron distribution within molecules and ions.
General rules to calculate oxidation states include the assignment of 0 to elements in their standard state, and -2 to oxygen in most compounds (except for peroxides and superoxides). Fluorine always has an oxidation state of -1 due to its high electronegativity. For ions, the oxidation state is equal to the charge of the ion.
General rules to calculate oxidation states include the assignment of 0 to elements in their standard state, and -2 to oxygen in most compounds (except for peroxides and superoxides). Fluorine always has an oxidation state of -1 due to its high electronegativity. For ions, the oxidation state is equal to the charge of the ion.