\(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+6 \mathrm{I}+14 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_{2} \mathrm{O}+3 \mathrm{I}_{2}\) Equivalent weight of \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\) is: (a) \(\mathrm{M} / 3\) (b) \(\mathrm{M} / 6\) (c) \(\mathrm{M} / 2\) (d) None of these

Short Answer

Expert verified
The equivalent weight of \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\) is \(\mathrm{M} / 6\).

Step by step solution

01

Understanding the Concept of Equivalent Weight

The equivalent weight of a substance is defined as the mass of that substance which combines with or displaces 1.008 grams (the atomic weight of hydrogen) or 8 grams of oxygen or 35.5 grams of chlorine. This usually corresponds to the mass of the substance that is involved in an exchange of one mole of electrons in a redox reaction.
02

Identifying the Change in Oxidation State for Chromium

The chromium atom in dichromate, \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\), is in the +6 oxidation state and it is reduced to the +3 oxidation state in chromium ion, \(\mathrm{Cr}^{3+}\). To find the total change in oxidation state for one mole of dichromate ion, calculate the change per chromium atom and multiply by 2, since there are two chromium atoms in one dichromate ion.
03

Calculating the Total Change in Oxidation State for Dichromate

The oxidation state of chromium in \(\mathrm{Cr}^{3+}\) is +3. The change in oxidation state per chromium atom is from +6 to +3, which is a decrease of 3. Thus, for two chromium atoms, the total change is \(2 \times 3 = 6\).
04

Calculating the Equivalent Weight of Dichromate

To find the equivalent weight of \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\), divide the molecular weight (M) by the total change in oxidation states for one mole of dichromate ions. The molecular weight for one mole of dichromate is given by M (since it is not specified, we use M as a general term for the molecular weight). Dividing the molecular weight by the total change in number of electrons per mole (which is 6 in this case), we get the equivalent weight as \(\frac{M}{6}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reaction
A redox reaction, short for reduction-oxidation reaction, is a chemical process involving the transfer of electrons between two substances. These reactions are characterized by changes in the oxidation states of atoms.
During a redox reaction, one substance gains electrons (reduction) while another loses electrons (oxidation). Electrons are transferred from the oxidizing agent, causing it to be reduced, to the reducing agent, causing it to be oxidized. This reciprocal process is fundamental to many chemical reactions, such as the one in our exercise:
\[\begin{equation} \mathrm{Cr}_2\mathrm{O}_7^{2-} + 6\mathrm{I} + 14\mathrm{H}^{+} \longrightarrow 2\mathrm{Cr}^{3+} + 7\mathrm{H}_2\mathrm{O} + 3\mathrm{I}_2 \end{equation}\]
The dichromate ion \(\mathrm{Cr}_2\mathrm{O}_7^{2-}\) reduces into \(\mathrm{Cr}^{3+}\), thus showing a loss of electrons. Simultaneously, iodine ions gain electrons to form iodine molecules, \(\mathrm{I}_2\). This highlights the redox characteristic of gaining and losing electrons.
Oxidation State
Oxidation state, often referred to as oxidation number, is a concept that provides a way to keep track of electrons in atoms during chemical reactions, particularly redox processes. It's a theoretical number that represents the electric charge an atom would have if the compound was composed of ions.
In redox reactions, the oxidation states of atoms change as electrons are transferred. These changes must be balanced, as the total number of electrons lost by one species must equal the number of electrons gained by another. In the given exercise, the oxidation state of \(\mathrm{Cr}\) in the dichromate ion \(\mathrm{Cr}_2\mathrm{O}_7^{2-}\) is +6, and it becomes +3 in \(\mathrm{Cr}^{3+}\). The change in the oxidation state here is essential for determining the equivalent weight of the compound.
Molecular Weight
Molecular weight, sometimes referred to as molecular mass, is the sum of the atomic weights of all atoms in a molecule. It's a measure of the total mass of a molecule and is often used in stoichiometry calculations for chemical reactions.
In the context of equivalent weight calculations, the molecular weight becomes a critical factor. Equivalent weight is defined as the mass of a substance that reacts with a given mass of another substance, such as hydrogen or oxygen, or that leads to the transfer of one mole of electrons in a redox reaction.Considering the exercise, we use the symbol \(M\) to represent the molecular weight of the dichromate ion \(\mathrm{Cr}_2\mathrm{O}_7^{2-}\), as the specific value is not given. To calculate the equivalent weight, this molecular weight is divided by the total change in oxidation states, providing a straightforward relationship between these parameters in chemistry.

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Most popular questions from this chapter

Calculate the weight of copper that will be deposited at the cathode in the electrolysis of a \(0.2 \mathrm{M}\) solution of copper sulphate, when quantity of electricity, equal to the required to liberate \(2.24 \mathrm{~L}\) of hydrogen at STP from a \(0.1 \mathrm{M}\) aqueous sulphuric acid, is passed (Atomic mass of \(\mathrm{Cu}=63.5\) ): (a) \(6.35 \mathrm{~g}\) (b) \(3.17 \mathrm{~g}\) (c) \(12.71 \mathrm{~g}\) (d) \(63.5 \mathrm{~g}\)

The standard reduction potentials of \(\mathrm{Zn}^{2+} \mid \mathrm{Zn}\) and \(\mathrm{Cu}^{2+} \mid \mathrm{Cu}\) are \(-0.76 \mathrm{~V}\) and \(+0.34 \mathrm{~V}\) respectively. What is the cell emf (in \(\mathrm{V}\) ) of the following cell? (RT/ \(F=0.059):\) \(\mathrm{Zn}\left|\mathrm{Zn}^{2+}(0.05 \mathrm{M}) \| \mathrm{Cu}^{2+}(0.005 \mathrm{M})\right| \mathrm{Cu}\) (a) \(1.1295\) (b) \(1.0705\) (c) \(1.1\) (d) \(1.041\)

The equivalent conductance at infinite dilution of \(\mathrm{HCl}\) and \(\mathrm{NaCl}\) are \(426.15\) and \(126.15 \mathrm{mho} \mathrm{cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}\) respectively. It can be said that the mobility of: (a) \(\mathrm{H}^{+}\) ions is much more than that of \(\mathrm{Cl}\) " ions (b) \(\mathrm{Cl}^{-}\) ions is much more than that of \(\mathrm{H}^{+}\) ions (c) \(\mathrm{H}^{+}\) ions is much more than that of \(\mathrm{Na}^{+}\) ions (d) \(\mathrm{Na}^{+}\) ions is much more than that of \(\mathrm{H}^{+}\) ions

Among the following, identify the species with an atom in \(+6\) oxidation state: (a) \(\mathrm{MnO}_{4}^{-}\) (b) \(\mathrm{Cr}(\mathrm{CN})_{6}^{3-}\) (c) \(\mathrm{NiF}_{6}^{2-}\) (d) \(\mathrm{CrO}_{2} \mathrm{Cl}_{2}\)

Calculate the weight of copper that will be deposited at the cathode in the electrolysis of a \(0.2 \mathrm{M}\) solution of copper sulphate, when quantity of electricity, equal to the required to liberate \(2.24 \mathrm{~L}\) of hydrogen at STP from a \(0.1 \mathrm{M}\) aqueous sulphuric acid, is passed (Atomic mass of \(\mathrm{Cu}=63.5\) ): (a) \(6.35 \mathrm{~g}\) (b) \(3.17 \mathrm{~g}\) (c) \(12.71 \mathrm{~g}\) (d) \(63.5 \mathrm{~g}\)

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