Chapter 3: Problem 81
The emf of a Daniell cell at \(298 \mathrm{~K}\) is \(\mathrm{E}_{-1}\) \(\mathrm{Zn}\left|\mathrm{ZnSO}_{4} \| \mathrm{CuSO}_{4}\right| \mathrm{Cu}\) \((0.01 \mathrm{M}) \quad(1.0 \mathrm{M})\) when the concentration of \(\mathrm{ZnSO}_{4}\) is \(1.0 \mathrm{M}\) and that of \(\mathrm{CuSO}_{4}\) is \(0.01 \mathrm{M}\), the emf changed to \(\mathrm{E}_{2}\). What is the relationship between \(\mathrm{E}_{1}\) and \(\mathrm{E}_{2} ?\) (a) \(\mathrm{E}_{1}=\mathrm{E}_{2}\) (b) \(\mathrm{E}_{2}=\mathrm{O} \neq \mathrm{E}_{1}\) (c) \(\mathrm{E}_{1}>\mathrm{E}_{2}\) (d) \(\mathrm{E}_{1}<\mathrm{E}_{2}\)
Short Answer
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