The function of catalyst in chemical reaction is to: (a) Increase the product (b) Decrease the product (c) Accelerate the rate of reaction (d) Increase the reactants

Short Answer

Expert verified
The function of a catalyst in a chemical reaction is to (c) accelerate the rate of reaction.

Step by step solution

01

Understanding the Role of a Catalyst

A catalyst is a substance that increases the rate of a chemical reaction without being consumed in the process. It provides an alternative pathway for the reaction to occur with a lower activation energy.
02

Evaluating the Options

With the understanding that a catalyst affects the rate of reaction, we can evaluate the options provided. We can eliminate options (a) and (b) since they discuss the quantity of products, and (d) as it mentions reactants. Option (c) directly states the effect of a catalyst on the rate of reaction.
03

Determining the Correct Answer

The correct answer must align with the definition and role of a catalyst. Therefore, the function of a catalyst in a chemical reaction is to accelerate the rate of the reaction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the branch of chemistry that deals with the speed or rate at which a chemical reaction occurs and the factors that affect this rate. It's like the 'time management' of chemical reactions—understanding what makes them go faster or slower. A significant aspect of chemical kinetics is the study of reaction rates and how various conditions, like temperature, pressure, and the presence of a catalyst, can influence them.

A catalyst, a substance that we consider the 'helper' in a chemistry scenario, plays a crucial role in chemical kinetics. It speeds up reactions by providing an alternative pathway for the reaction to occur that requires lower energy, which we refer to as activation energy (more on that shortly). Understanding chemical kinetics is crucial for controlling reactions in industrial processes, developing new chemicals, and studying biological systems. For example, in the production of ammonia through the Haber process, a catalyst is used to increase the reaction rate, making the process more efficient and cost-effective.
Activation Energy
Activation energy is kind of like the initial 'push' that reactants need to undergo a chemical transformation. Imagine a boulder at the top of a hill—it won't roll down until you give it a nudge. Activation energy is that nudge for chemical reactions. It's the minimum amount of energy that reacting particles must have for a reaction to occur.

Now, here's where the catalyst comes into play. It works by lowering this 'nudge'—the activation energy—making it easier for reactants to transform into products. Think of a catalyst as a shortcut on a hiking trail. The hikers (reactants) can reach their destination (the products) faster by taking a shortcut rather than the longer path. However, unlike the energy you expend hiking, the activation energy is conserved, and the catalyst provides a pathway where less energy is used.
Rate of Reaction
Rate of reaction is a measure of how quickly reactants turn into products in a chemical reaction. It's like timing how fast a runner completes a race—the faster the runner, the quicker the race ends. In chemistry, we might measure the rate at which a gas is produced or a solid dissolves. Factors such as concentration, temperature, surface area, and the use of a catalyst affect the reaction rate.

A catalyst is the 'personal trainer' for reactants, helping to increase the rate of reaction without being used up itself. It speeds up the chemical race but doesn't run the race. By lowering the activation energy, a catalyst ensures that more particles have enough energy to react at any given moment, thus increasing the frequency of reactions. This is why in many industrial processes, catalysts are key components—they help in achieving the desired product faster and more economically without being consumed in the procedure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The rate of reaction was found to be equal to its rate constant at any concentration of the reactant. The order of the reaction is: (a) Zero-order (b) First-order (c) Second-order (d) Third-order

The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at \(25^{\circ} \mathrm{C}\) are \(3.0 \times 10^{-4} \mathrm{~s}^{-1}, 104.4 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(6 \times 10^{14} \mathrm{~s}^{-1}\) respectively:

The temperature coefficient of most of the reactions lies between: (a) 1 and 3 (b) 2 and 3 (c) 1 and 2 (d) 2 and 4

For a zero-order reaction, the plot of concentration vs time is linear with: (a) +ve slope and zero intercept (b) - ve slope and zero intercept (c) +ve slope and non-zero intercept (d) - ve slope and non-zero intercept

Which one of the following equations is correct for the reaction: \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{~g}) ?\) (a) \(\frac{1}{3} \frac{\mathrm{d}\left[\mathrm{NH}_{3}\right]}{\mathrm{dt}}=\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{H}_{2}\right]}{\mathrm{dt}}\) (b) \(\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{NH}_{3}\right]}{\mathrm{dt}}=\frac{1}{-3} \frac{\mathrm{d}\left[\mathrm{H}_{2}\right]}{\mathrm{dt}}\) (c) \(\frac{1}{2} \frac{d\left[\mathrm{NH}_{3}\right]}{\mathrm{dt}}=\frac{1}{3} \frac{\mathrm{d}\left[\mathrm{H}_{2}\right]}{\mathrm{dt}}\) (d) \(\frac{1}{3} \frac{\mathrm{d}\left[\mathrm{NH}_{3}\right]}{\mathrm{dt}}=\frac{1}{-2} \frac{\mathrm{d}\left[\mathrm{H}_{2}\right]}{\mathrm{dt}}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free