The rate constant of first-order reaction is \(3 \times 10^{-6}\) per second. The initial concentration is \(0.10 \mathrm{M}\). The initial rate is: (a) \(3 \times 10^{-7} \mathrm{Ms}^{-1}\) (b) \(3 \times 10^{-4} \mathrm{Ms}^{-1}\) (c) \(3 \times 10^{-5} \mathrm{Ms}^{-1}\) (d) \(3 \times 10^{-6} \mathrm{Ms}^{-1}\)

Short Answer

Expert verified
The initial rate is \(3 \times 10^{-7} \mathrm{Ms}^{-1}\), which corresponds to option (a).

Step by step solution

01

Understanding First-Order Reactions

First-order reactions have a rate that is directly proportional to the concentration of one reactant. The rate law for a first-order reaction is given by the equation: rate = k[A], where k is the rate constant and [A] is the concentration of the reactant.
02

Applying the Rate Law

In this case, the rate constant k is given as \(3 \times 10^{-6}\) s^{-1}, and the initial concentration [A] is \(0.10 \mathrm{M}\). To find the initial rate, we multiply the rate constant by the initial concentration: rate = k[A] = \(3 \times 10^{-6} \times 0.10\).
03

Calculating the Initial Rate

Multiplying the rate constant by the initial concentration gives us the initial rate: \(3 \times 10^{-6} \times 0.10 = 3 \times 10^{-7} \mathrm{Ms}^{-1}\), which is option (a).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constant
The rate constant is a vital factor in the field of reaction kinetics, as it quantifies the speed of a chemical reaction. In a first-order reaction, the rate constant has units of reciprocal seconds (\text{s}^{-1}\text{)} and can be considered a measure of how quickly a reactant is consumed. This value remains constant regardless of the concentration of the reactants. The rate constant is determined experimentally and is affected by factors such as temperature and the presence of a catalyst.

For instance, with a rate constant (\text{k}\text{)} of \(3 \times 10^{-6}\) per second, we understand that for every second that passes, the reaction progresses at a consistent pace dictated by this value. It's crucial to clarify that the rate constant does not change with reactant concentration, but the overall rate of reaction does change as the concentration of reactants vary over time. In simpler terms, while \(k\) is immutable in a given set of conditions, the actual reaction rate you measure will still depend on how much reactant is there to work with initially.
Reaction Kinetics
Reaction kinetics is the study of the rates of chemical processes and the factors that affect these rates. It tells us how fast reactants transform into products. In first-order reactions, the rate is directly proportional to the concentration of one reactant. This means, if we double the concentration of the reactant, the rate of the reaction would also double.

In the step-by-step solution provided, we see this in action: the rate of the reaction is calculated by multiplying the rate constant by the initial concentration. Understanding the principles of reaction kinetics allows scientists and engineers to manipulate reaction conditions to optimize product yield, control energy usage, and ensure safety in industrial processes. Through this lens, we see how kinetics bridges the gap between microscopic interactions and real-world chemical applications.
Chemical Concentration
Chemical concentration refers to the amount of a substance in a given volume of solution, often expressed in molarity (M), which is moles per liter (mol/L). In reaction kinetics, the concentration is a dynamic quantity, changing as reactants are converted into products. For example, when we start with an initial concentration of \(0.10\) M and apply our understanding of first-order reaction kinetics, we can predict how this concentration will decline over time.

When solving for the initial rate, the concentration is critical because it directly impacts the reaction rate. In our exercise, it's the amount of reactant available at the beginning of the reaction (\(0.10\) M), which, coupled with the rate constant, enables us to calculate the initial rate of reaction. It's always important to clearly distinguish initial concentration from the changing concentrations as the reaction progresses. It's this interplay of concentration and rate constant that gives us a complete picture of reaction kinetics, allowing us to understand and control chemical processes.

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Most popular questions from this chapter

For the reaction \(\mathrm{A} \longrightarrow\) Products, it is found that the rate of reaction increases by a factor of \(6.25\), when the concentration of \(\mathrm{A}\) is increased by a factor of \(2.5\). The order of reaction with respect to \(\mathrm{A}\) is: (a) \(0.5\) (b) 1 (c) 2 (d) 3

Which of the following statements is correct? (1) Order of a reaction can be known from experimental results and not from the stoichiometry of a reaction. (2) Molecularity a reaction refers to (i) each of the elementary steps in (an overall mechanism of) a complex reaction or (ii) a single step reaction. (3) Overall molecularity of a reaction may be determined in a manner similar to overall order of reaction. (4) Overall order of a reaction \(\mathrm{A}^{\mathrm{m}}+\mathrm{B}^{\mathrm{n}} \longrightarrow \mathrm{AB}_{\mathrm{x}}\) is \(\mathrm{m}+\mathrm{n}\) Select the correct answer using the following codes: (a) 2 and 3 (b) 1,3 and 4 (c) 2,3 and 4 (d) 1,2 and 3

The unit of second-order reaction rate constant is: (a) \(\mathrm{L}^{-1} \cdot \mathrm{mol}^{-1} \mathrm{~d} \mathrm{~s}^{-1}\) (b) \(\mathrm{L}^{2} \mathrm{~mol}^{-2} \mathrm{~s}^{-1}\) (c) L. \(\mathrm{mol}^{-1} \mathrm{~s}^{-1}\) (d) \(\mathrm{s}^{-1}\)

The reaction \(\mathrm{X} \longrightarrow\) Product follows first-order kinetics, hi 40 minutes, the concentration of \(X\) changes from \(0.1 \mathrm{M}\) to \(0.025 \mathrm{M}\), then the rate of reaction when concentration of \(\mathrm{X}\) is \(0.01 \mathrm{M}\) is: (a) \(3.47 \times 10^{-5} \mathrm{M} / \mathrm{min}\) (b) \(1.73 \times 10^{-4} \mathrm{M} / \mathrm{min}\) (c) \(1.73 \times 10^{-5} \mathrm{M} / \mathrm{min}\) (d) \(3.47 \times 10^{-4} \mathrm{M} / \mathrm{min}\)

The temperature dependence of rate constant (A) of a chemical reaction is written in terms of Arrhenius equation, \(=\mathrm{A} \cdot \mathrm{e}^{-\mathrm{E} / \mathrm{RT}}\), Activation energy \(\mathrm{E}_{3}\) of the reaction can be calculated by ploting: (a) \(\log \mathrm{k} \operatorname{vs} \mathrm{T}^{-1}\) (b) \(\log \mathrm{k} \mathrm{vs} \frac{1}{\log \mathrm{T}}\) (c) \(k \operatorname{vs} \mathrm{T}\) (d) \(\mathrm{k} \mathrm{vs} \frac{1}{\log \mathrm{T}}\)

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