Chapter 6: Problem 91
A metal gives two chlorides \(\mathrm{A}\) and \(\mathrm{B}\). A gives black precipitate with \(\mathrm{NH}_{3}\) and \(\mathrm{B}\) gives white. With KI, B gives a yellow precipitate, which is soluble in excess of KI. A and B are respectively (a) \(\mathrm{Hg}_{2} \mathrm{Cl}_{2}, \mathrm{HgCl}_{2}\) (b) \(\mathrm{HgCl}, \mathrm{Hg}_{2} \mathrm{Cl}_{2}\) (c) \(\mathrm{ZnCl}_{2}, \mathrm{HgCl}_{2}\) (d) \(\mathrm{HgCl}_{2}, \mathrm{ZnCl}_{2}\)
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.