Chapter 7: Problem 108
A hydride (a) of group 15 element is distinctly basic and has unexpectably high boiling point. It reacts with \(\mathrm{NaOCl}\) to give another hydride (b) which is a strong reducing agent and is used in organic analysis. A and \(\mathrm{B}\) are (a) \(\mathrm{NH}_{3}, \mathrm{~N}_{2} \mathrm{H}_{4}\) (b) \(\mathrm{PH}_{3}, \mathrm{P}_{2} \mathrm{H}_{4}\) (c) \(\mathrm{NH}_{3}, \mathrm{NH}_{4} \mathrm{Cl}\) (d) \(\mathrm{AsH}_{3}, \mathrm{As}_{2} \mathrm{H}_{4}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.