Chapter 7: Problem 111
Maximum percentage of available chlorine on the basis of \(\mathrm{CaOCl}_{2} . \mathrm{H}_{2} \mathrm{O}\) formula is: (a) 40 (b) 35 (c) 49 (d) 45
Short Answer
Expert verified
None of the options match the calculated percentage of available chlorine which is approximately 49.23%. The closest option is (c) 49.
Step by step solution
01
Write down the formula of the compound and calculate its molar mass
The chemical formula for the given compound is \(\mathrm{CaOCl}_2.\mathrm{H}_2\mathrm{O}\). First, calculate the molar mass by adding up the atomic masses of all atoms in the formula. Calcium (Ca) has an atomic mass of 40.08 g/mol, oxygen (O) 16.00 g/mol, chlorine (Cl) 35.45 g/mol, and hydrogen (H) 1.008 g/mol.
02
Calculate the molar mass of the compound
The molar mass of the compound is calculated as follows: one Ca (40.08 g/mol), one O (16.00 g/mol), two Cl's (2 * 35.45 g/mol), two H's (2 * 1.008 g/mol), and one O for water (16.00 g/mol). Total molar mass = 40.08 + 16.00 + (2 * 35.45) + (2 * 1.008) + 16.00 = 144.008 g/mol.
03
Calculate molar mass of chlorine in the compound
To find the available chlorine percentage, you need the total mass of chlorine in one mole of the compound. Since there are two chlorine atoms in one formula unit, their combined molar mass is 2 * 35.45 g/mol = 70.90 g/mol.
04
Calculate the percentage of available chlorine
To get the percentage, divide the molar mass of chlorine by the molar mass of the compound and multiply by 100%. \(\frac{70.90\, g/mol}{144.008\, g/mol} \times 100\% = 49.23\%\) (rounded to two decimal places). This value is higher than all the options given, implying there might be a need to check the rounding of atomic masses or that the provided options are incorrect.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Stoichiometry
Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in chemical reactions. It is essentially the calculations around converting moles from one substance to moles of another, based on the balanced chemical equation. Understanding stoichiometry is crucial because it ensures that the equations are balanced in terms of both mass and charge. For example, knowing the stoichiometry of a chemical compound such as calcium oxychloride,
To solve problems involving stoichiometry, you begin by balancing the chemical equation, then convert quantities of known substances into moles using their molar masses before applying the mole ratio from the balanced equation to find the amount of the desired substance.
CaOCl2⋅H2O
, can inform us of how much chlorine we can 'access' or utilize from the compound, which is particularly important in applications such as disinfection.To solve problems involving stoichiometry, you begin by balancing the chemical equation, then convert quantities of known substances into moles using their molar masses before applying the mole ratio from the balanced equation to find the amount of the desired substance.
Molar Mass Calculation
The molar mass of a substance is the mass of one mole of its particles (atoms, molecules, ions, etc.) and is expressed in grams per mole (g/mol). Calculating molar mass is a fundamental step in stoichiometric calculations as it directly relates mass to the number of moles. To calculate the molar mass of a compound, like
CaOCl2⋅H2O
, you simply sum the atomic masses of all the atoms present in one molecule of that compound. Here's a simplified visual breakdown:- One calcium (Ca): 40.08 g/mol
- One oxygen (O): 16.00 g/mol
- Two chlorines (Cl), each 35.45 g/mol, thus 70.90 g/mol for both
- Two hydrogens (H) and one oxygen (O) in the water molecule, comprising 18.016 g/mol
Chemical Composition
The chemical composition of a substance defines what elements it contains and in what proportions. Knowing the chemical composition helps to understand the properties, usage, and behavior of the substance in various reactions. For example, calcium oxychloride,
To accurately assess the chemical composition, it's essential to account for all constituents and their proportions. This is pivotal for applications such as calculating available chlorine in disinfectants, where the effectiveness of the product depends on the concentration of active chlorine in the compound.
CaOCl2⋅H2O
, contains calcium, oxygen, chlorine, and hydrogen. The proportion of the chlorine element within the compound determines its 'available chlorine content'—this is the amount of chlorine that can be utilized for its oxidizing power. The percentage calculation ties stoichiometry and molar mass concepts together. By understanding chemical composition, we can deduce the roles different elements play, whether it's in forming compounds, reacting with other substances, or in providing specific functional characteristics to materials and products.To accurately assess the chemical composition, it's essential to account for all constituents and their proportions. This is pivotal for applications such as calculating available chlorine in disinfectants, where the effectiveness of the product depends on the concentration of active chlorine in the compound.