Chapter 7: Problem 17
In which of the following compounds, oxygen exhibits an oxidation state of \(+2\) ? (a) \(\mathrm{H}_{2} \mathrm{O}_{2}\) (b) \(\mathrm{OF}_{2}\) (c) \(\mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{H}_{2} \mathrm{SO}_{4}\)
Short Answer
Expert verified
Option (b) OF_2 is the compound in which oxygen exhibits an oxidation state of (+2).
Step by step solution
01
Recall the Oxidation State Rules
The oxidation state of oxygen is typically (-2) in most compounds. However, there are exceptions, such as in peroxides (HO_2) where it is (-1), and in compounds with more electronegative elements (like fluorine), where it can be positive.
02
Analyze Option (a) - H_2O_2
Using the oxidation state rule for peroxides, each oxygen in H_2O_2 has an oxidation state of (-1) because H_2O_2 is a peroxide. Therefore, option (a) is not correct.
03
Analyze Option (b) - OF_2
Fluorine (F) has a higher electronegativity than oxygen and is always assigned an oxidation state of (-1) in its compounds. Since there are two fluorines, the total oxidation for fluorine is (-2). To balance this, oxygen must have an oxidation state of (+2). Hence, option (b) is correct.
04
Analyze Option (c) - H_2O
In water (H_2O), the hydrogens (H) each have an oxidation state of (+1), and since there are two of them, oxygen must balance this with an oxidation state of (-2). Therefore, option (c) is not correct.
05
Analyze Option (d) - H_2SO_4
In sulfuric acid (H_2SO_4), oxygen typically has an oxidation state of (-2). Even though sulfur has a positive oxidation state, the oxygen atoms do not have an oxidation state of (+2) in this molecule. Therefore, option (d) is not correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Chemical Compounds
Chemical compounds are substances formed by the chemical combination of two or more elements in definite proportions and held together by chemical bonds. Each element within a compound is present in a specific ratio, giving the compound its unique properties. For instance, water, with its molecular formula of H2O, consists of two hydrogen atoms bonded to one oxygen atom. The properties of compounds are determined by the nature of the elements involved and how they are bonded together.
Identifying each element's oxidation state in a compound is crucial to understanding its chemical behavior. For example, in hydrogen peroxide (H2O2), oxygen has a different oxidation state than in water because of the arrangement and type of bonds between the atoms. As we explore the various compounds such as H2O2, OF2, H2O, and H2SO4, we notice that oxygen's oxidation state varies, providing insight into the compound's chemical reactivity and how it might interact with other substances.
Identifying each element's oxidation state in a compound is crucial to understanding its chemical behavior. For example, in hydrogen peroxide (H2O2), oxygen has a different oxidation state than in water because of the arrangement and type of bonds between the atoms. As we explore the various compounds such as H2O2, OF2, H2O, and H2SO4, we notice that oxygen's oxidation state varies, providing insight into the compound's chemical reactivity and how it might interact with other substances.
Oxidation Rules Explained
The oxidation state, often known as the oxidation number, is a concept used in chemistry to help keep track of electron transfers in oxidation-reduction (redox) reactions. Oxidation states are assigned to atoms based on a set of rules. Typically, the oxidation state of oxygen in compounds is -2, but there are exceptions that we need to be aware of:
To determine the oxidation state of an element in a compound, one must consider these rules alongside the total charge of the molecule. By applying these principles, as done in the steps of our solution, we can deduce that in the compound OF2, oxygen has a rare positive oxidation state of +2 to balance the more electronegative fluorines.
- In peroxides, such as H2O2, each oxygen atom has an oxidation state of -1 due to the single bond between the two oxygen atoms.
- With more electronegative elements like fluorine, oxygen can have a positive oxidation state because fluorine will attract the bonding electrons more strongly, as seen in compounds like OF2.
To determine the oxidation state of an element in a compound, one must consider these rules alongside the total charge of the molecule. By applying these principles, as done in the steps of our solution, we can deduce that in the compound OF2, oxygen has a rare positive oxidation state of +2 to balance the more electronegative fluorines.
Electronegativity and Its Role
Electronegativity is a measure of an atom's ability to attract and hold onto electrons within a chemical bond. It is a fundamental property that affects how atoms interact with each other in a molecule. The Pauling scale is the most commonly used system to quantify electronegativity, with higher values indicating greater electronegativity.
In the context of determining oxidation states, electronegativity plays a pivotal role. Typically, the more electronegative element in a bond acquires a negative oxidation state due to its ability to attract shared electrons. For example, fluorine is the most electronegative element and will almost always have an oxidation state of -1 in its compounds, overpowering oxygen's usual oxidation state of -2.
In the case of OF2, because fluorine (F) is more electronegative than oxygen (O), it retains a -1 oxidation state, while oxygen (O), being less electronegative in this scenario, is assigned a +2 oxidation state. Understanding how electronegativity determines the distribution of electrons in a compound can help predict the compound's chemical and physical properties.
In the context of determining oxidation states, electronegativity plays a pivotal role. Typically, the more electronegative element in a bond acquires a negative oxidation state due to its ability to attract shared electrons. For example, fluorine is the most electronegative element and will almost always have an oxidation state of -1 in its compounds, overpowering oxygen's usual oxidation state of -2.
In the case of OF2, because fluorine (F) is more electronegative than oxygen (O), it retains a -1 oxidation state, while oxygen (O), being less electronegative in this scenario, is assigned a +2 oxidation state. Understanding how electronegativity determines the distribution of electrons in a compound can help predict the compound's chemical and physical properties.