Which of the following bonds will be most polar? (a) \(\mathrm{O}-\mathrm{F}\) (b) \(\mathrm{N}-\mathrm{F}\) (c) \(\mathrm{N}-\mathrm{N}\) (d) \(\mathrm{N}-\mathrm{Cl}\)

Short Answer

Expert verified
The most polar bond among the given options is (b) \(\mathrm{N}-\mathrm{F}\).

Step by step solution

01

Understand Polarity

Polarity of a bond is determined by the difference in electronegativity between the two atoms forming the bond. The greater the difference, the more polar the bond.
02

Compare Electronegativities

Look up the electronegativities of the atoms involved in each bond. Fluorine has the highest electronegativity, followed by oxygen, chlorine, and nitrogen, in that order.
03

Calculate Electronegativity Differences

Calculate the difference in electronegativity for each bond. The bond with the largest difference in electronegativity will be the most polar. (a) \(\mathrm{O}-\mathrm{F}\): difference significant; \(\mathrm{N}-\mathrm{F}\): difference is larger; \(\mathrm{N}-\mathrm{N}\): no difference; \(\mathrm{N}-\mathrm{Cl}\): difference smaller than \(\mathrm{N}-\mathrm{F}\) and \(\mathrm{O}-\mathrm{F}\).
04

Identify the Most Polar Bond

Considering the electronegativity values, \(\mathrm{N}-\mathrm{F}\) bond has a larger difference in electronegativity than the other options, making it the most polar bond.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity
Electronegativity is a fundamental concept within the realm of chemistry that helps us understand how atoms interact with each other. It refers to the ability of an atom within a molecule to attract shared electrons in a chemical bond towards itself.

The electronegativity value of an element is a unitless numerical value that can be found on the Pauling scale, with fluorine being the most electronegative element with a value of approximately 3.98. Generally, electronegativity increases across a period and decreases down a group on the periodic table.

Understanding electronegativity is crucial because it allows us to predict and explain the polarity of bonds, which in turn influences the physical properties of compounds such as melting point, boiling point, and solubility.
Chemical Bonding
The connection between atoms that enables the formation of chemical substances containing two or more atoms is known as chemical bonding. The two main types of bonds are ionic and covalent bonds, which are based on the transfer or sharing of electrons, respectively.

An ionic bond occurs between a metal and a non-metal, where one atom donates electrons to another, leading to the formation of ions that attract each other due to opposite charges. Conversely, a covalent bond is formed between non-metal atoms that share pairs of electrons.

The difference in electronegativity between bonding atoms causes the electron density to be unevenly distributed, resulting in partially positive and negative poles - a concept that is essential when considering the polarity of molecules and their resultant behaviors and interactions.
Polar Versus Nonpolar Bonds
The polarity of a chemical bond is an essential concept distinguishing between polar and nonpolar molecules. A polar bond occurs when there is a significant difference in electronegativity between the bonded atoms, causing a dipole moment where electron density is higher around the more electronegative atom. This leads to partial negative and positive charges on each end of the bond, much like a magnet with north and south poles.

Common examples of polar molecules include water (H2O), where the oxygen is more electronegative than the hydrogen. On the other hand, nonpolar bonds are typically formed between atoms of the same or similar electronegativity, resulting in an even distribution of electron density. Examples include diatomic gases like nitrogen (N2) and oxygen (O2), where the electrons are shared equally.

The polarity of bonds influences the intermolecular forces between molecules, which are critical for understanding the substance's state of matter, solubility, and reactivity, among other properties.

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Most popular questions from this chapter

\(\mathrm{N}\) forms \(\mathrm{NCl}_{3}\) whereas \(\mathrm{P}\) can form both \(\mathrm{PCl}_{3}\) and \(\mathrm{PCl}_{5}\). Why? (a) \(\mathrm{N}\) atoms is larger than \(\mathrm{P}\) in size (b) \(\mathrm{P}\) has low lying \(3 \mathrm{~d}\) -orbitals, which can be used for bonding but \(\mathrm{N}\) does not have any d-orbitals in its valence shell (c) \(\mathrm{P}\) is more reactive towards \(\mathrm{Cl}\) than \(\mathrm{N}\) (d) None of these

Dinitrogen trioxide is: (a) Anhydride of \(\mathrm{HNO}_{2}\) (b) Anhydride \(\mathrm{HNO}_{3}\) (c) Anhydride of \(\mathrm{H}_{2} \mathrm{~N}_{2} \mathrm{O}_{4}\) (d) Anhydride of \(\mathrm{HNO}_{4}\)

White phosphorous is more reactive than the nitrogen molecule because the (1) \(\mathrm{P}-\mathrm{P}\) bond in phosphorous is weaker than the \(\mathrm{N} \equiv\) N bond in nitrogen (2) \(\mathrm{P}-\mathrm{P}-\mathrm{P}\) bond angle is \(120^{\circ}\) whereas \(\mathrm{N}_{2}\) is linear (3) Electronegativity of phosphorous is low (4) Ionization energy of phosphorous is greater than of \(\mathrm{N}_{2}\)

A hydride (a) of group 15 element is distinctly basic and has unexpectably high boiling point. It reacts with \(\mathrm{NaOCl}\) to give another hydride (b) which is a strong reducing agent and is used in organic analysis. A and \(\mathrm{B}\) are (a) \(\mathrm{NH}_{3}, \mathrm{~N}_{2} \mathrm{H}_{4}\) (b) \(\mathrm{PH}_{3}, \mathrm{P}_{2} \mathrm{H}_{4}\) (c) \(\mathrm{NH}_{3}, \mathrm{NH}_{4} \mathrm{Cl}\) (d) \(\mathrm{AsH}_{3}, \mathrm{As}_{2} \mathrm{H}_{4}\)

What is the Haber's process? (a) The synthesis of hydrazine, \(\mathrm{N}_{2} \mathrm{H}_{4}\) (b) The synthesis of nitric acid, \(\mathrm{HNO}_{3}\) (c) The isolation of \(\mathrm{N}_{2}\) from the atmosphere (d) The synthesis of ammonia, \(\mathrm{NH}_{3}\)

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