Chapter 9: Problem 35
The oxidation state of oxygen in \(\mathrm{O}_{2}\left[\mathrm{PtF}_{6}\right]\) is: (a) \(-1 / 2\) (b) \(+2\) (c) \(+1 / 2\) (d) \(+1\)
Short Answer
Expert verified
-1/2
Step by step solution
01
Understand the Concept of Oxidation States
In a molecule, the oxidation state of an element is the charge it would have if all bonds to atoms of different elements were 100% ionic. In general, oxygen has an oxidation state of -2 in most of its compounds, but there are exceptions.
02
Recognize the Exception for Peroxides
Peroxides are a class of compounds where oxygen has an oxidation state of -1. This is due to the O-O bond shared between the two oxygen atoms. In the given molecule of \(\mathrm{O}_2\left[\mathrm{PtF}_6\right]\), the oxygen molecule \(\mathrm{O}_2\) is in a peroxide linkage.
03
Calculate the Average Oxidation State of Oxygen in the Peroxide
Since in peroxides each oxygen has an oxidation state of -1, and there are two of them, the total oxidation state for the two oxygen atoms is -2. To find the average oxidation state per oxygen atom, divide the total oxidation state by the number of oxygen atoms: \(\frac{-2}{2} = -1\).
04
Express the Oxidation State as a Fraction
The oxidation state found in step 3 is an integer. Since one of the answer choices is expressed as a fraction (a), we convert the integer to a fraction as follows: \( -1 = -\frac{1}{1} = -\frac{2}{2} = -\frac{1}{2} \times 2 = -\frac{1}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Peroxide Linkage
Oxygen is a versatile element, known primarily for its general oxidation state of -2 when it combines with other elements. However, in the special case of peroxide compounds, we encounter what is known as a peroxide linkage. This unique feature occurs when two oxygen atoms are directly connected to each other, forming an O-O bond within a molecule.
In peroxides, unlike in most other oxygen-containing compounds, each oxygen atom has an oxidation state of -1. This deviates from the common -2 state due to the shared electrons between the two oxygen atoms in the peroxide bond. Essentially, each oxygen atom keeps one additional electron from its usual share, leading to this less negative oxidation state.
Hydrogen peroxide (H2O2) is a classic example of a peroxide, where the O-O peroxide linkage is clearly present. The distinctive '-1' oxidation state in peroxides is a crucial exception to remember, as it plays into further understanding of oxidation states in compounds and molecular interactions.
In peroxides, unlike in most other oxygen-containing compounds, each oxygen atom has an oxidation state of -1. This deviates from the common -2 state due to the shared electrons between the two oxygen atoms in the peroxide bond. Essentially, each oxygen atom keeps one additional electron from its usual share, leading to this less negative oxidation state.
Hydrogen peroxide (H2O2) is a classic example of a peroxide, where the O-O peroxide linkage is clearly present. The distinctive '-1' oxidation state in peroxides is a crucial exception to remember, as it plays into further understanding of oxidation states in compounds and molecular interactions.
Calculation of Oxidation States
Understanding the calculation of oxidation states is fundamental for grasping many concepts in chemistry, especially when delving into redox reactions and the balancing of chemical equations. The oxidation state can be thought of as the hypothetical charge an atom would carry if all its bonds were ionic, with the electrons being donated to the more electronegative element.
To determine oxidation states, we follow a set of rules:
To determine oxidation states, we follow a set of rules:
- For an atom in its elemental form, the oxidation state is always zero.
- For a monatomic ion, the oxidation state is equal to the ion's charge.
- Fluorine always has an oxidation state of -1 in its compounds.
- Hydrogen is usually +1 (except when it forms hydrides with metals, where it is -1).
- Oxygen is usually -2, but with exceptions like in peroxides.
Oxygen Oxidation Number Exceptions
While oxygen typically exhibits an oxidation state of -2, there are notable exceptions that every chemistry student should recognize. These include:
- In peroxides such as H2O2, oxygen has an oxidation state of -1 due to the peroxide linkage, as discussed previously.
- In superoxides, which contain the superoxide anion (O2-), each oxygen atom has an oxidation state of -1/2.
- When bonded to fluorine, which is more electronegative, oxygen can have a positive oxidation state, as fluorine will always be -1.