The number of oxygen atoms present in 1 mole of oxalic acid dihydrate is (a) \(6 \times 10^{2^{2}}\) (b) \(6.022 \times 10^{34}\) (c) \(7.22 \times 10^{23}\) (d) \(36.13 \times 10^{23}\)

Short Answer

Expert verified
6.022 x 10^{23} oxygen atoms.

Step by step solution

01

Understanding the Molecule

Recognize that oxalic acid dihydrate is written chemically as C2H2O4.2H2O. In one molecule of oxalic acid dihydrate, there are a total of 4 oxygen atoms from the oxalic acid part and 2 additional oxygen atoms from the two water molecules, making a total of 6 oxygen atoms per molecule.
02

Avogadro's Number

Recall that one mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23 particles/mole.
03

Calculate the Total Number of Oxygen Atoms

Multiply the number of oxygen atoms in one molecule by Avogadro's number to find the total number of oxygen atoms in one mole of oxalic acid dihydrate: 6 oxygen atoms/molecule x 6.022 x 10^23 molecules/mole.
04

Perform the Multiplication

Carry out the multiplication to yield the total number of oxygen atoms in one mole of oxalic acid dihydrate: 6 x 6.022 x 10^23 = 36.132 x 10^23. However, we usually express significant figures properly, and since we aren't given precision for the number of oxygen atoms in a molecule, we assume it to be an exact number. Hence, we usually write the number of atoms in scientific notation rounded appropriately: 6.022 x 10^23.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Number
At the heart of chemistry lies a fundamental measurement often referred to as Avogadro's number. This number, approximately equal to \(6.022 \times 10^{23}\), is the quantity of atoms, ions, or molecules contained in one mole of a substance. Named after the Italian scientist Amedeo Avogadro, it allows chemists to count particles by weighing them.

Avogadro's number connects the macroscopic world we can measure, such as grams of a substance, to the microscopic world of atoms and molecules. This constant forms the bridge between an element's atomic mass on the periodic table and the grams of a substance necessary to have a mole of particles.

When solving problems involving Avogadro's number, it's important to ensure that your units cancel out correctly and to express your final answer to the appropriate number of significant figures, as this number is foundational to subsequent calculations in chemistry.
Chemical Formula
A chemical formula represents the types of atoms and their respective quantities in a substance. For instance, the chemical formula of oxalic acid dihydrate is \(C_2H_2O_4\cdot 2H_2O\), which shows not only the elements that are part of the compound but also the number of each atom in a molecule.

The chemical formula can be interpreted in two parts: the actual compound oxalic acid \((C_2H_2O_4)\), and its hydration part \((2H_2O)\), representing the two water molecules associated with each molecule of oxalic acid. Such details are crucial because they convey the exact structure of the compound, which in turn affects the stoichiometry and the mole concept application.

Understanding the chemical formula is a critical step before any calculations. Knowing the components allows for a direct count of specific atoms in a molecule, such as oxygen in the context of the given exercise, ensuring accuracy when determining the number of atoms in a mole of the substance.
Stoichiometry
Stoichiometry is the quantitative aspect of chemistry that involves calculating the relationships between reactants and products in a chemical reaction. It is based on the conservation of mass and the concept of moles. Through stoichiometry, we can predict how much of a substance is needed or produced in a reaction.

For example, knowing the number of moles and atoms in oxalic acid dihydrate allows us to perform calculations to figure out the weight of a given number of oxygen atoms or to predict how much product will result from a certain amount of reactant. It also lets us scale reactions up or down in a controlled and predictable way.

When improving your stoichiometric calculations, focus on balanced chemical equations, awareness of limiting reactants, and the precise use of conversion factors that incorporate Avogadro's number and molar masses. These skills ensure you're not just getting the answer right, but understanding the process and quantities involved, forming a solid foundation for more advanced chemical analysis.

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Most popular questions from this chapter

Which of the following correctly represents \(180 \mathrm{~g}\) of water? (i) 5 moles of water (ii) 10 moles of water (iii) \(6.023 \times 10^{23}\) molecules of water (iv) \(6.023 \times 10^{24}\) molecules of water (a) (i) and (ii) (b) (i) and (iv) (c) (ii) ând (iv) (d) (ii) and (iii)

Which of the following rules regarding the significant figures and calculations involving them is not correct? (a) The result of an addition or subtraction is reported to the same number of decimal places as present in number with least decimal places. (b) Result of multiplication or division should have same number of significant figures as present in most precise figure. (c) The result of multiplication or division should be rounded off to same number of significant figures as present in least precise figure. (d) Thenon-significantfiguresinthemeasurements are rounded off.

A compound contains two elements \(^{*} X^{\prime}\) and ' \(Y^{\prime}\) in the ratio of \(50 \%\) each. Atomic mass of \(^{\prime} X^{*}\) is 20 and \({ }^{\prime} Y\) is \(40 .\) What can be its simplest formula? (a) \(X Y\) (b) \(X_{2} Y\) (c) \(X Y_{2}\) (d) \(X_{2} Y_{3}\)

One atom of an element weighs \(3.32 \times 10^{-23} \mathrm{~g}\). How many number of gram atoms are there in \(20 \mathrm{~kg}\) of the element? (a) 2000 (b) 20 (c) 200 (d) 1000

The relative number of atoms of elements, ' \(\boldsymbol{X}\) and \({ }^{\prime} Y^{\prime}\) in a compound is \(0.25\) and \(0.5\). The empirical formula of compound is (a) \(X Y\) (b) \(X_{2} Y\) (c) \(\mathrm{XY}_{2}\) (d) \(X_{2} Y_{2}\)

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