Slaked lime reacts with chlorine to give (a) \(\mathrm{CaCl}_{2}\) (b) \(\mathrm{CaO}\) (c) \(\mathrm{Ca}(\mathrm{OCl})_{2}\) (d) \(\mathrm{CaCO}_{3}\)

Short Answer

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\mathrm{Ca(OCl)}_{2}

Step by step solution

01

Identify the Reactants

The problem states that slaked lime, which is chemically known as calcium hydroxide \(\mathrm{Ca(OH)}_{2}\), reacts with chlorine \(\mathrm{Cl}_{2}\).
02

Write Down the Chemical Reaction

The chemical reaction between calcium hydroxide and chlorine can be represented as: \(\mathrm{Ca(OH)}_{2} + \mathrm{Cl}_{2} \rightarrow \mathrm{Ca}({OCl})_{2} + \mathrm{H}_{2}\mathrm{O}\).
03

Identify the Product

From the reaction, it is clear that the product formed is calcium oxychloride \(\mathrm{Ca(OCl)}_{2}\), which is identifiable amongst the provided options.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equations
In chemistry, a chemical equation is a symbolic representation of a chemical reaction. It shows the reactants transforming into products, with each substance written using its chemical formula. For instance, when calcium hydroxide reacts with chlorine, the reaction can be depicted as \(\mathrm{Ca(OH)_2 + Cl_2 \rightarrow Ca(OCl)_2 + H_2O}\). It's important to balance a chemical equation to follow the Law of Conservation of Mass, which states that mass is neither created nor destroyed in a chemical reaction. The equation provided is already balanced, indicating that equal numbers of each type of atom are present on both sides of the reaction arrow.

To improve understanding, remember that the left side lists reactants, substances before the reaction, and the right side lists products, the substances formed as a result of the reaction. Place coefficients, whole numbers placed in front of chemical formulas, to balance the equation, ensuring the same quantity of each atom is reflected on both sides.
Reactivity of Chlorine
Chlorine \(\mathrm{Cl_2}\) is a highly reactive, green-yellow gas that plays a significant role in many chemical reactions. Reactivity refers to how readily a chemical species engages in chemical reactions. Chlorine is a member of the halogen group and has a strong tendency to gain electrons and form chloride ions \(\mathrm{Cl^-}\). This reactivity allows chlorine to form a variety of compounds, ranging from inorganic salts to organic chlorine compounds. In the reaction \(\mathrm{Ca(OH)_2 + Cl_2 \rightarrow Ca(OCl)_2 + H_2O}\), chlorine reacts with slaked lime to produce calcium oxychloride and water, showing chlorine's ability to react with both metals and non-metals.

When considering safety, chlorine's reactivity must be handled with caution, as it can be harmful to health and the environment, emphasizing the need for proper chemical handling protocols.
Properties of Slaked Lime
Slaked lime, scientifically known as calcium hydroxide \(\mathrm{Ca(OH)_2}\), is a white powdery substance obtained by mixing calcium oxide with water. It's slightly soluble in water, forming a suspension known as lime water, which is used in various applications including construction and wastewater treatment. Slaked lime has a basic pH and can neutralize acids, making it valuable in chemical processes requiring pH control. It's caustic and should be handled with suitable protection to avoid skin burns.

The compound's ability to react with acids and other substances like chlorine to form various compounds, including the sanitizing agent calcium oxychloride, showcases slaked lime's chemical versatility.
Formation of Calcium Oxychloride
Calcium oxychloride \(\mathrm{Ca(OCl)_2}\), also known as bleaching powder, is formed when slaked lime (calcium hydroxide) reacts with chlorine. The chemical reaction can be summarized as \(\mathrm{Ca(OH)_2 + Cl_2 \rightarrow Ca(OCl)_2 + H_2O}\). Calcium oxychloride has disinfectant properties and is used in water treatment and as a bleach. This compound has a dual nature due to the presence of calcium, chlorine, and oxygen atoms, making it effective in various reactions. In particular, it acts as both a source of chlorine and an oxidizing agent. These properties make it useful not only for sanitizing but also in the field of organic chemistry for oxidation reactions.

Understanding the formation and uses of calcium oxychloride helps in grasping the broader implications of chemical reactions between common substances like chlorine and slaked lime.

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Most popular questions from this chapter

A solution of a compound \(X\) in dilute \(\mathrm{HCl}\) on treatment with a solution of \(\mathrm{BaCl}_{2}\) gives a white precipitate of a compound \(Y\) which is insoluble in coac. \(\mathrm{HNO}_{3}\) and conc. \(\mathrm{HCl}\). Compound \(X\) imparts golden yellow colour to the flame. yellow colour) What are compounds \(X\) and \(Y ?\) (a) \(X\) is \(\mathrm{MgCl}_{2}\) and \(Y\) is \(\mathrm{BaSO}_{4}\)(b) \(X\) is \(\mathrm{CaCl}_{2}\) and \(Y\) is \(\mathrm{BaSO}_{4}\) (c) \(X\) is \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) and \(Y\) is \(\mathrm{BaSO}_{4}\) (d) \(X\) is \(\mathrm{MgSO}_{4}\) and \(Y\) is \(\mathrm{BaSO}_{4}\)

Alkali metals cannot be extracted by reduction of their oxides and other compounds because (a) alkali metals are strong reducing agents (b) alkali metals have low ionisation enthalpy (c) alkali metals have high lattice enthalpy (d) alkali metals are strongly basic in nature.

An oxide of allkaline earth metals \((X)\) reacts with \(\mathrm{C}\) and \(\mathrm{Cl}_{2}\) to give a compound \(Y . Y\) is found in polymeric chain structure and is electron deficient molecule. The compound \(Y\) is (a) \(\mathrm{BeO}\) (b) \(\mathrm{BeCl}_{2}\) (c) \(\mathrm{Be}(\mathrm{OH})_{2}\) (d) \(\mathrm{BeCO}_{3}\)

\begin{aligned} &\text { The mobilities of the alkali metal tons in aqueous }\\\ &\text { solution are } \mathrm{Li}^{+}<\mathrm{Na}^{*}<\mathrm{K}^{+}<\mathrm{Rb}^{+}<\mathrm{Cs}^{*} \text { because } \end{aligned}(a) greater is the degree of hydration, lesser is the mobility in aqueous medium (b) larger the size of cation, greater is the mobility in aqueous medium (c) larger the size of cation, lesser is the mobility of ions in aqueous medium (d) lesser the degree of hydration, lesser is the mobility of ions in aqueous medium.

Which of the following metals is required as cofactor by all enzymes utilising ATP in phosphate transfer? (a) \(\mathrm{K}\) (b) \(\overline{\mathrm{Ca}}\) (c) \(\mathrm{Na}\) (d) \(\mathrm{Mg}\)

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