In which of the following the inert pair effect is most prominent? (a) C (b) Ge (c) Si (d) \(\mathrm{Pb}\)

Short Answer

Expert verified
Lead (\text{Pb}) exhibits the most prominent inert pair effect.

Step by step solution

01

Understanding the Inert Pair Effect

The inert pair effect refers to the reluctance of the s-electrons in the outermost electron shell (specifically the s2 pair) to participate in bonding as we move down a group in the periodic table. This effect is more prominent in heavier elements (those with higher atomic numbers) within a group, particularly in post-transition metals.
02

Identifying the Position of Elements in the Periodic Table

To determine which element exhibits the most prominent inert pair effect, identify the position of each element in the periodic table. Carbon (C) is in Group 14 and Period 2, Germanium (Ge) and Silicon (Si) are also in Group 14 but are in Period 4 and Period 3 respectively, and Lead (Pb) is in Group 14 and Period 6.
03

Comparing the Atomic Numbers

Compare the atomic numbers of the elements to assess which one is the heaviest. Carbon has an atomic number of 6, Silicon has 14, Germanium has 32, and Lead has 82.
04

Determining the Most Prominent Inert Pair Effect

Since the inert pair effect becomes more significant with increasing atomic number within a group, and Lead (Pb) has the highest atomic number among the given elements, it will exhibit the most prominent inert pair effect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Periodic Table
The periodic table is a fundamental tool in chemistry that organizes all known chemical elements in a tabular arrangement according to their atomic number, electron configurations, and recurring chemical properties. Elements are arranged in rows called periods and columns known as groups.

In the context of the inert pair effect, the periodic table helps us locate the position of elements within their respective groups. For example, when considering Group 14, which includes Carbon (C), Silicon (Si), Germanium (Ge), and Lead (Pb), we can observe that as we move down the group, the atomic number increases. This provides a visual representation of why elements like Lead exhibit a stronger inert pair effect.

Moreover, by observing the position in the periodic table, students can predict various chemical properties and reactive behaviors of elements, which is essential in understanding chemical bonding and reactivity.
The Significance of Chemical Bonding
Chemical bonding is the force that holds atoms together in chemical compounds. There are several types of chemical bonds, with the main ones being ionic, covalent, and metallic bonds.

In the s-block elements of the periodic table, which consists of the alkali metals and alkaline earth metals, the outer s-electrons are usually involved in the formation of chemical bonds. As we progress to the p-block elements, the inert pair effect comes into play, where the reluctance of the s-electrons in the outer shell to participate in bonding is observed. This can affect the type of compounds formed and their stability.

Understanding chemical bonding is crucial because it determines the structure and properties of molecules. For students, it is important to comprehend the concept of the inert pair effect, as it not only influences the valency of elements but also their overall chemistry, including oxidation states and the types of compounds they are likely to form.
Characteristics of Post-Transition Metals
Post-transition metals are located on the periodic table to the right of the transition metal block. These elements, such as tin (Sn), lead (Pb), and bismuth (Bi), typically display a mixture of metallic and non-metallic properties and are often associated with the inert pair effect.

As we observe in the exercise, Lead (Pb) is the element where the inert pair effect is most prominent. This is characteristic of post-transition metals, which have more pronounced reluctance of the s-electrons to participate in bonding due to their higher atomic numbers and unique electron configurations. Notably, their chemical behavior can become quite complex as a result of this effect.

When studying post-transition metals, it's crucial to consider their position in the periodic table, as this can also impact their chemical reactivity and the types of bonds they can form. This group of metals often exhibits oxidation states that are lower than their group valency, which is directly related to the inert pair effect.

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Most popular questions from this chapter

A metal \(M\) reacts with sodium hydroxide to give a white precipitate \(X\) which is soluble in excess of \(\mathrm{NaOH}\) to give \(Y\). Compound \(X\) is soluble in \(\mathrm{HCl}\) to form a compound \(Z\). Identify \(M, X, Y\) and \(Z\). $$\begin{array}{lllc} \boldsymbol{M} & {\boldsymbol{X}} & {\mathbf{Y}} & \mathbf{Z} \\ (a)\mathrm{Si} & \mathrm{SiO}_{2} & \mathrm{Na}_{2} \mathrm{SiO}_{3} & \mathrm{SiCl}_{4} \\ (b)\mathrm{Al} & \mathrm{Al}(\mathrm{OH})_{3} & \mathrm{NaAlO}_{2} & \mathrm{AlCl}_{3} \\ (c)\mathrm{Mg} & \mathrm{Mg}(\mathrm{OH})_{3} & \mathrm{NaMgO}_{3} & \mathrm{MgCl}_{2} \\ (d)\mathrm{Ca} & \mathrm{Ca}(\mathrm{OH})_{2} & \mathrm{Na}_{2} \mathrm{CO}_{3} & \mathrm{NaHCO}_{3} \end{array}$$

The most stable form of carbon at high temperature is \(X\). The \(C\) - C bond length in diamond is \(Y\) while C - C bond length in graphite is \(Z\) What are \(X, Y\) and \(Z\) respectively? (a) Graphite, \(1.42 \AA, 1.54 \AA\) (b) Coke, \(1.54 \AA, 1.84 \AA\) (c) Diamond, \(1.54 \AA, 1.42 \AA\) (d) Fullerene, \(1.54 \AA, 1.54 \boldsymbol{A}\)

In \(\mathrm{SiO}_{4}^{4-}\), the tetrahedral molecule, two oxygen atoms are shared in (a) sheet silicates (b) double-chain silicates (c) chain silicates (d) three-dimensional silicates.

In graphite, \(\mathrm{C}\) atom is in.........state. (a) \(s p^{3}\) (b) \(s p\) (c) \(s p^{2}\) (d) None of these.

Why do boron and aluminium halides behave as Lewis acids? (a) Both halides \(\left(M X_{3}\right)\) can accept electrons from (a) a donor to complete their octet. (b) Both halides \(\left(M X_{3}\right)\) can donate a pair of electrons. (c) Both halides \(\left(M X_{3}\right)\) are covalent polymeric structures. (d) Both halides \(\left(M X_{3}\right)\) react with water to give hydroxides and \(\mathrm{HCl}\).

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