Which of the following is not an example of disproportionation reaction? (a) \(4 \mathrm{ClO}_{3}^{-} \rightarrow \mathrm{Cl}^{-}+3 \mathrm{ClO}_{4}^{-}\) (b) \(2 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}\) (c) \(2 \mathrm{NO}_{2}+2 \mathrm{OH}^{-} \rightarrow \mathrm{NO}_{2}^{-}+\mathrm{NO}_{3}^{-}+\mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{TiCl}_{4}+2 \mathrm{Mg} \rightarrow \mathrm{Ti}+2 \mathrm{MgCl}_{2}\)

Short Answer

Expert verified
Option (d) is not an example of a disproportionation reaction.

Step by step solution

01

Define Disproportionation Reaction

A disproportionation reaction is a specific type of redox reaction in which a single species is simultaneously oxidized and reduced, giving two different products with the element in question exhibiting a higher and a lower oxidation state compared to the original species.
02

Analyze Option (a)

In the reaction of option (a), chlorine starts with an oxidation state of +5 in \(\mathrm{ClO}_{3}^{-}\) and ends with oxidation states of -1 in \(\mathrm{Cl}^{-}\) and +7 in \(\mathrm{ClO}_{4}^{-}\). This shows both reduction and oxidation of chlorine, fitting the definition of a disproportionation reaction.
03

Analyze Option (b)

In the reaction of option (b), oxygen starts with an oxidation state of -1 in \(\mathrm{H}_{2}\mathrm{O}_{2}\) and ends with oxidation states of -2 in water and 0 in oxygen gas. Oxygen is both reduced and oxidized, which meets the criteria for a disproportionation reaction.
04

Analyze Option (c)

In the reaction of option (c), nitrogen starts with an oxidation state of +4 in \(\mathrm{NO}_{2}\) and ends with oxidation states of +3 in \(\mathrm{NO}_{2}^{-}\) and +5 in \(\mathrm{NO}_{3}^{-}\). This means nitrogen is both reduced to \(\mathrm{NO}_{2}^{-}\) and oxidized to \(\mathrm{NO}_{3}^{-}\), indicating that this is also a disproportionation reaction.
05

Analyze Option (d)

Looking at option (d), titanium starts in a +4 oxidation state in \(\mathrm{TiCl}_{4}\) and is reduced to a 0 oxidation state in titanium metal. Magnesium, starting at a 0 oxidation state, is oxidized to +2 in \(\mathrm{MgCl}_{2}\). This reaction involves the transfer of electrons between two different elements and does not involve the simultaneous oxidation and reduction of a single species. Thus, it is not a disproportionation reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox reactions
Redox reactions, or reduction-oxidation reactions, are chemical processes where the oxidation state of one or more atoms changes due to the transfer of electrons. These reactions are essential for many biochemical and industrial processes. In these reactions, there are two half-reactions: reduction, where an element gains electrons and its oxidation state decreases, and oxidation, where an element loses electrons and its oxidation state increases.

For instance, in the reaction where hydrogen peroxide decomposes into water and oxygen gas \(2 \text{H}_2 \text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2\), the oxygen in hydrogen peroxide, with an oxidation state of -1, is both reduced to -2 in water and oxidized to 0 in oxygen gas. Such chemical reactions where both reduction and oxidation occur simultaneously are the backbone of many natural and technological processes.
Oxidation states
The oxidation state, also referred to as oxidation number, is a number assigned to an element in a chemical compound that represents the number of electrons lost or gained by an atom of that element in the compound. It helps in determining how electrons are distributed in a molecule and which atoms are undergoing oxidation or reduction in redox reactions.

An element can have different oxidation states in different compounds or even in the same molecule. For example, chlorine in \(\text{ClO}_3^-\) has an oxidation state of +5, and in \(\text{Cl}^-\) it has an oxidation state of -1, as seen in the disproportionation reaction \(4 \text{ClO}_3^- \rightarrow \text{Cl}^-+3\text{ClO}_4^-\). Understanding oxidation states is crucial for analyzing redox processes, such as disproportionation reactions.
Chemical equations
Chemical equations are symbolic representations of chemical reactions, where reactants are transformed into products. These equations must be balanced, meaning that the number of atoms for each element must be the same on both sides of the equation. This reflects the law of conservation of mass.

For a disproportionation reaction to be properly represented, the chemical equation must illustrate the same element undergoing both oxidation and reduction, like in the reaction \(2 \text{NO}_2 + 2 \text{OH}^- \rightarrow\text{NO}_2^- + \text{NO}_3^- + \text{H}_2 \text{O}\) where nitrogen's oxidation states change from +4 to both +3 and +5. It's essential to understand how to read and write chemical equations to grasp the concept of disproportionation and other redox reactions.

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Most popular questions from this chapter

When a piece of sodium metal is dropped in water, hydrogen gas evolved because (a) sodium is reduced and acts as an oxidising agent (b) water is oxidised and acts as a reducing agent (c) sodium loses electrons and is oxidised while water in reduced (d) water loses electrons and is oxidised to hydrogen.

Write the following ions in order of decreasing capacity to accept electrons. \(\mathrm{H}^{+}, \mathrm{Mg}^{2+}, \mathrm{K}^{+}, \mathrm{Ag}^{+}, \mathrm{Zn}^{2+}\) (a) \(\mathrm{Ag}^{+}>\mathrm{H}^{+}>\mathrm{Zn}^{2+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}\) (b) \(\mathrm{H}^{+}>\mathrm{Zn}^{2+}>\mathrm{Mg}^{2+}>\mathrm{K}^{+}>\mathrm{Ag}^{+}\) (c) \(\mathrm{K}^{+}>\mathrm{Mg}^{2+}>\mathrm{Zn}^{2+}>\mathrm{H}^{+}>\mathrm{Ag}^{+}\) (d) \(\mathrm{Mg}^{2+}>\mathrm{Zn}^{2+}>\mathrm{K}^{+}>\mathrm{Ag}^{+}>\mathrm{H}^{+}\)

Which of the following is not a rule for calculating oxidation number? (a) For ions, oxidation number is equal to the charge on the ion. (b) The oxidation number of oxygen is \(-2\) in all of its compounds. (c) The oxidation number of fluorine is \(-1\) in all of its compounds. (d) Oxidation number of hydrogen is \(+1\) except in binary hydrides of alkali metals and alkaline earth metals where it is \(-1\).

A metal \(X\) displaces nickel from nickel sulphate solution but does not displace manganese from manganese sulphate solution. What is the correct order of their reducing powers? (a) \(\mathrm{Ni}>\mathrm{Mn}>X\) (b) \(X>\mathrm{Mn}>\mathrm{Ni}\) (c) \(\mathrm{Mn}>X>\mathrm{Ni}\) (d) \(\quad \mathrm{Mn}>\mathrm{Ni}>X\)

Oxidation numbers of \(\mathrm{Mn}\) in its compounds \(\mathrm{MnCl}_{2}\) \(\mathrm{Mn}(\mathrm{OH})_{3}, \mathrm{MnO}_{2}\) and \(\mathrm{KMnO}_{4}\) respectively are (a) \(+2,+4,+7,+3\) (b) \(+2,+3,+4,+7\) (c) \(+7,+3,+2,+4\) (d) \(+7,+4,+3,+2\)

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