Among \(\mathrm{NH}_{3}, \mathrm{H}_{2} \mathrm{O}, \mathrm{HF}\) and \(\mathrm{H}_{2} \mathrm{~S}\) which would have highest magnitude of hydrogen bonding? (a) HF due to maximum pobrity. (b) \(\mathrm{H}_{2} \mathrm{O}\) due to lone pairs of electrons. (c) \(\mathrm{NH}_{3}\) due to small size of nitrogen. (d) \(\mathrm{H}_{2} \mathrm{~S}\) due to higher electron affinity of sulphur

Short Answer

Expert verified
H2O would have the highest magnitude of hydrogen bonding due to oxygen's high electronegativity and the presence of two lone pairs.

Step by step solution

01

Understand Hydrogen Bonding

Hydrogen bonding is a special type of dipole-dipole attraction between molecules, where a hydrogen atom is attached to a highly electronegative element (like N, O, or F) and is attracted to another electronegative atom with a lone pair of electrons. The strength of hydrogen bonding is proportional to the polarity of the molecule and the ability of an atom to donate or receive a hydrogen bond.
02

Analyze Each Molecule

Examine each of the given molecules for electronegativity difference and the presence of lone pairs which can be used to form hydrogen bonds: (a) HF has a high electronegativity difference, (b) H2O has two lone pairs and oxygen is highly electronegative, (c) NH3 has one lone pair and nitrogen is less electronegative than oxygen, (d) H2S has low electronegativity difference and sulfur's ability to form hydrogen bond is less pronounced.
03

Determine the Highest Magnitude of Hydrogen Bonding

Considering both the electronegativity and the availability of lone pairs for hydrogen bonding, water (H2O) is expected to have the strongest hydrogen bonds due to oxygen's high electronegativity and the molecule’s geometry which allows for an optimal hydrogen bonding arrangement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity
Electronegativity is a chemical property that describes how strongly atoms attract electrons in a chemical bond. It's crucial for understanding the behavior of atoms in different molecules. The higher the electronegativity, the greater the atom's ability to attract electrons to itself. In the context of hydrogen bonding, it plays a key role because hydrogen bonds usually form between hydrogen and an atom with high electronegativity, such as nitrogen (N), oxygen (O), or fluorine (F).

Why is this important for hydrogen bonding? When an atom like oxygen, with a high electronegativity, is bonded to hydrogen, the uneven distribution of electrons creates a partial negative charge (delta-) on the oxygen and a partial positive charge (delta+) on the hydrogen. This polarity is a prerequisite for hydrogen bonding and affects how molecules will interact with each other. For example, in water (H2O), oxygen's high electronegativity allows it to pull the bonding electrons closer, creating a significant dipole that leads to strong hydrogen bonds with neighboring water molecules.
Dipole-Dipole Interactions
Dipole-dipole interactions occur between polar molecules, which possess regions of partial positive and negative charge, known as dipoles. These interactions are another type of intermolecular force that plays a critical part in the behavior of molecules. Molecules with greater dipoles will have stronger dipole-dipole interactions, leading to higher boiling points and melting points compared to similar, nonpolar molecules.

In regards to hydrogen bonding, which is a specific form of dipole-dipole attraction, the partially positive hydrogen atom of one molecule is attracted to the partial negative charge of an electronegative atom in a nearby molecule. This attraction contributes to the unique properties of substances like water, where each molecule can form multiple hydrogen bonds, resulting in a high boiling point and surface tension. Remembering that the polarity of a molecule enhances its ability to participate in dipole-dipole interactions and hydrogen bonding will help you anticipate the physical properties of substances.
Lone Pairs of Electrons
Lone pairs of electrons refer to the pair of valence electrons that are not shared with another atom in a chemical bond. These lone pairs are particularly important in the formation of hydrogen bonds. Molecules with lone pairs on highly electronegative atoms like oxygen or nitrogen can act as hydrogen bond acceptors. This means they can interact with the partially positive hydrogen on a polar molecule to form a hydrogen bond.

For instance, in water (H2O), the oxygen atom has two lone pairs of electrons which can attract the hydrogen atoms of adjacent water molecules, leading to the formation of a strong network of hydrogen bonds. This explains why water has a relatively high boiling point and unique properties such as its solid form (ice) being less dense than its liquid form. Oxygen's ability to form two hydrogen bonds per molecule because of its lone pairs results in a three-dimensional lattice when frozen, making ice less dense than the liquid. As illustrated in the exercise, the presence of lone pairs on highly electronegative atoms is a key factor in determining the strength of hydrogen bonding in a molecule.

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Most popular questions from this chapter

Polyphosphates like sodium hexametaphosphate (calgon) are used as water softening agents because they (a) form soluble complexes with anionic species (b) precipitate anionic species (c) form soluble complexes with cationic species (d) precipitate cationic species.

Which of the following statements regarding hydrogen peroxide is false? (a) It is a strong oxidising agent. (b) It is decomposed by \(\mathrm{MnO}_{2}\). (c) It behaves as a reducing agent. (d) It is more stable in basic solution.

Which of the following metals will react with \(\mathrm{NaOH}\) and \(\mathrm{KOH}\) to liberate hydrogen gas? (a) \(\mathrm{Zn}, \mathrm{Al}, \mathrm{Fe}\) and \(\mathrm{Mg}\) (b) Al, Fe, \(\mathrm{Mg}\) and \(\mathrm{Sn}\) (c) \(\mathrm{Zn}, \mathrm{Sn}\) and \(\mathrm{Al}\) (d) \(\mathrm{Fe}, \mathrm{Mg}\) and \(\mathrm{Al}\)

Which of the following represents the chemical equation involved in the preparation of \(\mathrm{H}_{2} \mathrm{O}_{2}\) from barium peroxide? (a) \(\mathrm{BaO}_{2} \cdot 8 \mathrm{H}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}+8 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{CH}_{3} \mathrm{CHOHCH}_{3}+\mathrm{O}_{2} \rightarrow \mathrm{CH}_{3} \mathrm{COCH}_{3}+\mathrm{H}_{2} \mathrm{O}_{2}\) (c) \(\mathrm{BaO}_{2}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{BaCO}_{3}+\mathrm{H}_{2} \mathrm{O}_{2}\) (d) \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}+3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow 3 \mathrm{BaSO}_{4}+2 \mathrm{H}_{3} \mathrm{PO}_{4}\)

Which property of hydrogen is shown by the following reactions? (i) \(\mathrm{Fe}_{3} \mathrm{O}_{4}+4 \mathrm{H}_{2} \rightarrow 3 \mathrm{Fe}+4 \mathrm{H}_{2} \mathrm{O}\) (ii) \(\mathrm{CO}+\mathrm{H}_{2} \stackrel{\mathrm{ZnO},}{\mathrm{Cr}_{2} \mathrm{O}_{3}} \mathrm{CH}_{3} \mathrm{OH}\) (a) Reducing character (b) Oxidising character (c) Combustibility (d) High reactivity

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