Provide the missing reactant or reaction condition for the following: (a) \(\mathrm{n}\) -heptane \(+\underline{\text { ? }}\) * toluene (b) Iodobenzene \(+\underline{?}\) biphenyl (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCH}_{3}+?\) \+ ethyl benzene

Short Answer

Expert verified
The missing reactants and reaction conditions for each reaction are: (a) \(\mathrm{CH_3Cl}\) and \(\mathrm{AlCl_3}\) (b) \(\mathrm{Mg}\) and ether (c) \(\mathrm{H_2}\) and \(\mathrm{Pd/C}\)

Step by step solution

01

In this reaction, we need to add a reactant which can lead to the formation of toluene. This means we need to remove a hydrogen molecule from n-heptane and substitute it with a methyl group. For this transformation, we need a reagent that can promote the necessary substitution. #Step 2: Determine the missing reactant for n-heptane and toluene#

A reagent that can be used for this purpose is chloromethane (\(\mathrm{CH_3Cl}\)), in the presence of a catalyst such as aluminum chloride (\(\mathrm{AlCl_3}\)). The reaction can be written as: \[\text{n-heptane} + \mathrm{CH_3Cl} \xrightarrow{\mathrm{AlCl_3}} \text{toluene}\] #Step 3: Identify the reaction for Iodobenzene and biphenyl#
02

In this reaction, we need to add a reactant which can lead to the formation of biphenyl. This means we need to couple two phenyl rings together. For this transformation, we need a reagent that can promote the necessary coupling. #Step 4: Determine the missing reactant for Iodobenzene and biphenyl#

A reagent that can be used for this purpose is magnesium metal (\(\mathrm{Mg}\)), in the presence of a suitable solvent like ether. This is a typical example of a Grignard reaction. The reaction can be written as: \[\text{iodobenzene} + \mathrm{Mg} \xrightarrow{\text{ether}} \text{biphenyl}\] #Step 5: Identify the reaction for \(\mathrm{C_6H_5COCH_3}\) and ethyl benzene#
03

In this reaction, we need to add a reactant which can lead to the formation of ethyl benzene. This means we need to remove an \(\mathrm{COCH_3}\) group from the given reactant and replace it with a hydrogen atom. For this transformation, we need a reagent that can promote the necessary reduction and replacement. #Step 6: Determine the missing reactant for \(\mathrm{C_6H_5COCH_3}\) and ethyl benzene#

A reagent that can be used for this purpose is hydrogen gas (\(\mathrm{H_2}\)), in the presence of a catalyst such as palladium (\(\mathrm{Pd}\)) on carbon. The reaction can be written as: \[\text{\(\mathrm{C_6H_5COCH_3}\)} + \mathrm{H_2} \xrightarrow{\mathrm{Pd/C}} \text{ethyl benzene}\] So, the missing reactants and reaction conditions are as follows: a) \(\mathrm{CH_3Cl}\) and \(\mathrm{AlCl_3}\) b) \(\mathrm{Mg}\) and ether c) \(\mathrm{H_2}\) and \(\mathrm{Pd/C}\)

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