Suggest a synthesis for each of the following, using nitrobenzene and any other necessary reagents. (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~N}=\mathrm{NC}_{6} \mathrm{H}_{5}\) (c) \(\mathrm{p}-\mathrm{CH}_{3} \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHOH}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{ND}_{2}\)

Short Answer

Expert verified
(a) To synthesize Azobenzene (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~N}=\mathrm{NC}_{6} \mathrm{H}_{5}\)), follow these steps: 1. Reduce nitrobenzene to aniline (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\)) using \(\mathrm{Sn}/\mathrm{HCl}\). 2. Form diazonium salt (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{N}_{2}^{+} \mathrm{Cl}^{-}\)) with nitrous acid (\(\mathrm{HNO}_2\)) using sodium nitrite (\(\mathrm{NaNO}_2\)) and hydrochloric acid (\(\mathrm{HCl}\)). 3. Perform coupling reaction with another equivalent of aniline to produce azobenzene. (c) To synthesize p-Toluidine (\(\mathrm{p}-\mathrm{CH}_{3} \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\)): 1. Nitrate nitrobenzene to obtain 1,3-dinitrobenzene using a mixture of \(\mathrm{HNO}_3\) and \(\mathrm{H}_{2} \mathrm{SO}_{4}\). 2. Reduce 1,3-dinitrobenzene to 3-nitroaniline using \(\mathrm{Fe}/\mathrm{HCl}\). 3. Alkylate 3-nitroaniline using methyl chloride (\(\mathrm{CH}_{3} \mathrm{Cl}\)) and \(\mathrm{AlCl}_3\) (Friedel-Crafts Alkylation) to obtain p-toluidine. (b) To synthesize Phenylhydroxylamine (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHOH}\)): 1. Partially reduce nitrobenzene to nitrosobenzene (\(\mathrm{C}_6\mathrm{H}_5\mathrm{NO}\)) using \(\mathrm{Zn}/\mathrm{HCl}\). 2. Reduce nitrosobenzene with lithium aluminum hydride (\(\mathrm{LiAlH}_4\)) in THF to obtain phenylhydroxylamine. (d) To synthesize Benzene-d2-amine (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{ND}_{2}\)): 1. Reduce nitrobenzene to aniline (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\)) using \(\mathrm{Sn}/\mathrm{HCl}\). 2. Replace N-H with N-D using deuterium and a transition metal catalyst, such as palladium/carbon (\(\mathrm{Pd/C}\)), to yield benzene-d2-amine.

Step by step solution

01

- Reduction of nitrobenzene to aniline

Start with the reduction of nitrobenzene to aniline using a reducing agent such as \(\mathrm{Sn}/\mathrm{HCl}\). This will give \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\).
02

- Formation of diazonium salt

Next, react aniline with nitrous acid (\(\mathrm{HNO}_2\)) in cold conditions to form a diazonium salt (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{N}_{2}^{+} \mathrm{Cl}^{-}\)). This reaction is facilitated using sodium nitrite (\(\mathrm{NaNO}_2\)) and hydrochloric acid (\(\mathrm{HCl}\)) as reagents.
03

- Coupling reaction

Lastly, react the diazonium salt with another equivalent of aniline to perform a coupling reaction. This will produce the target compound azobenzene (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~N}=\mathrm{NC}_{6} \mathrm{H}_{5}\)). (c) Synthesis of p-Toluidine (\(\mathrm{p}-\mathrm{CH}_{3} \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\)):
04

- Nitration of nitrobenzene

Start by nitrating nitrobenzene using a mixture of nitric acid (\(\mathrm{HNO}_3\)) and sulfuric acid (\(\mathrm{H}_{2} \mathrm{SO}_{4}\)) as the nitrating agent to obtain the 1,3-dinitrobenzene intermediate.
05

- Reduction of 1,3-dinitrobenzene

Next, reduce 1,3-dinitrobenzene using a reducing agent such as \(\mathrm{Fe}/\mathrm{HCl}\) to produce 3-nitroaniline.
06

- Friedel-Crafts Alkylation

Finally, alkylate 3-nitroaniline using methyl chloride (\(\mathrm{CH}_{3} \mathrm{Cl}\)) and \(\mathrm{AlCl}_3\) (Friedel-Crafts Alkylation) to obtain p-toluidine (\(\mathrm{p}-\mathrm{CH}_{3} \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\)). (b) Synthesis of Phenylhydroxylamine (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHOH}\)):
07

- Reduction of nitrobenzene to nitrosobenzene

Start by reducing nitrobenzene using \(\mathrm{Zn}/\mathrm{HCl}\) in a partial reduction to obtain nitrosobenzene (\(\mathrm{C}_6\mathrm{H}_5\mathrm{NO}\)).
08

- Reduction of nitrosobenzene

Next, reduce nitrosobenzene using lithium aluminum hydride (\(\mathrm{LiAlH}_4\)) in THF (tetrahydrofuran) to obtain phenylhydroxylamine (\(\mathrm{C}_6\mathrm{H}_5\mathrm{NHOH}\)). (d) Synthesis of Benzene-d2-amine (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{ND}_{2}\):
09

- Reduction of nitrobenzene to aniline

Start by reducing nitrobenzene to aniline using a reducing agent such as \(\mathrm{Sn}/\mathrm{HCl}\), giving \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\).
10

- Replacement of N-H with N-D

Lastly, replace the N-H group with N-D by adding deuterium in the presence of a transition metal catalyst, such as palladium/carbon (\(\mathrm{Pd/C}\)). This will yield benzene-d2-amine (\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{ND}_{2}\)).

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