Give for each of the following pairs of compounds a chemical test, preferably a test-tube reaction, that will distinguish the two compounds. Write a structural formula for each compound and equations for the reactions involved: (a) \(\mathrm{m}\) -niltrotoluene and phenylnitromethane (b) \(\mathrm{p}\) -nitrotoluene and benzamide (c) hydrazobenzene and benzidine (d) \(\mathrm{p}\) -methoxyazobenzene and \(\mathrm{p}\) -methylazoxybenzene (e) aniline and cyclohexylamine.

Short Answer

Expert verified
(a) Hydrolysis with sodium hydroxide (\(\mathrm{NaOH}\)): m-nitrotoluene → m-aminotoluene + \(\mathrm{NaNO}_{2}\); Phenylnitromethane → benzylamine + \(\mathrm{HNO}_{2}\). (b) Reaction with ammonia: Benzamide → \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{CONH}_{4}\) (crystalline product). (c) Oxidation reaction: Hydrazobenzene → azobenzene. (d) Acid-catalyzed hydrolysis with \(\mathrm{HCl}\): p-methylazoxybenzene → \(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{N}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{OH}\) + \(\mathrm{CH}_{3}\mathrm{Cl}\). (e) Reaction with bromine water: Aniline → \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{N}\mathrm{Br}_{2}\) (white precipitate).

Step by step solution

01

Draw the structural formulas

The structural formulas are as follows: - m-nitrotoluene: \(\mathrm{C}_{6}\mathrm{H}_{4}\mathrm{NO}_{2}\)-\(\mathrm{CH}_{3}\) - phenylnitromethane: \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{CH}_{2}\mathrm{NO}_{2}\)
02

Find a suitable chemical test

A suitable chemical test that can distinguish between m-nitrotoluene and phenylnitromethane is a hydrolysis reaction, which will yield different products for each compound. The hydrolysis can be carried out in alkaline conditions using a solution of sodium hydroxide (\(\mathrm{NaOH}\)).
03

Write the chemical equations

The chemical equations for the chosen test are: m-nitrotoluene + \(\mathrm{NaOH}\) → hydrolysis → m-aminotoluene + \(\mathrm{NaNO}_{2}\); Phenylnitromethane + \(\mathrm{NaOH}\) → hydrolysis → benzylamine + \(\mathrm{HNO}_{2}\). (b) p-nitrotoluene and benzamide
04

Draw the structural formulas

The structural formulas are as follows: - p-nitrotoluene: \(\mathrm{C}_{6}\mathrm{H}_{4}\mathrm{NO}_{2}\)-\(\mathrm{CH}_{3}\) - benzamide: \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{CONH}_{2}\)
05

Find a suitable chemical test

To distinguish p-nitrotoluene and benzamide, we can use the reaction of ammonia with the compound. Benzamide will react with ammonia to form a crystalline product while p-nitrotoluene will not react.
06

Write the chemical equations

The chemical equation for the chosen test is: benzamide + ammonia → \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{CONH}_{4}\) (crystalline product) (c) hydrazobenzene and benzidine
07

Draw the structural formulas

The structural formulas are as follows: - hydrazobenzene: \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{N}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{5}\) - benzidine: \(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{NH}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{NH}_{2}\)
08

Find a suitable chemical test

For hydrazobenzene and benzidine, we can use oxidation reaction. Hydrazobenzene on oxidation will form azobenzene (\(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{N}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{5}\)) and benzidine will not participate in oxidation.
09

Write the chemical equations

The chemical equation for the chosen test is: hydrazobenzene + oxidizing agent → azobenzene (d) p-methoxyazobenzene and p-methylazoxybenzene
10

Draw the structural formulas

The structural formulas are as follows: - p-methoxyazobenzene: \(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{N}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{OCH}_{3}\) - p-methylazoxybenzene: \(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{N}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{O}\)-\(\mathrm{CH}_{3}\)
11

Find a suitable chemical test

We can use acid-catalyzed hydrolysis to distinguish between p-methoxyazobenzene and p-methylazoxybenzene. p-methylazoxybenzene will react with dilute aqueous hydrochloric acid (\(\mathrm{HCl}\)) while p-methoxyazobenzene will not.
12

Write the chemical equations

The chemical equation for the chosen test is: p-methylazoxybenzene + \(\mathrm{HCl}\) → \(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{N}_{2}\)-\(\mathrm{C}_{6}\mathrm{H}_{4}\)-\(\mathrm{OH}\) + \(\mathrm{CH}_{3}\mathrm{Cl}\) (e) aniline and cyclohexylamine
13

Draw the structural formulas

The structural formulas are as follows: - aniline: \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{NH}_{2}\) - cyclohexylamine: \(\mathrm{C}_{6}\mathrm{H}_{11}\)-\(\mathrm{NH}_{2}\)
14

Find a suitable chemical test

To distinguish aniline and cyclohexylamine, we can use bromine water. Aniline will react with bromine water, producing a white precipitate, while cyclohexylamine will not.
15

Write the chemical equations

The chemical equation for the chosen test is: aniline + Br₂(aq) → \(\mathrm{C}_{6}\mathrm{H}_{5}\)-\(\mathrm{N}\mathrm{Br}_{2}\) (white precipitate)

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