Pentacovalent phosphorus compounds normally have trigonal-bipyramidal structures. In such structures the more electro negative substituents show a strong preference for the apical positions. With these facts in mind, suggest an explanation for the following data obtained by nuclear magnetic resonance studies. \(\mathrm{CH}_{3} \mathrm{PF}_{4}: \quad\) one kind of methyl one kind of fluorine \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{PF}_{3}:\) one kind of methyl two kinds of fluorine in the ratio \(2: 1\) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{PF}_{2}:\) one kind of methyl two kinds of fluorine

Short Answer

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In pentacovalent phosphorus compounds with trigonal-bipyramidal structures, the more electronegative substituents prefer the apical positions. For \(\mathrm{CH}_{3} \mathrm{PF}_{4}\), the four fluorine atoms occupy apical positions and one methyl group is in the equatorial position, resulting in one kind of methyl and fluorine environment. In \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{PF}_{3}\), one fluorine atom occupies an apical position and two occupy equatorial positions, with two equatorial methyl groups, resulting in two kinds of fluorine in a 2:1 ratio and one kind of methyl environment. For \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{PF}_{2}\), the two fluorine atoms occupy apical positions, with three symmetry-equivalent equatorial methyl groups, resulting in one kind of methyl environment and two kinds of fluorine environments.

Step by step solution

01

Understand Trigonal Bipyramidal Structures

In a trigonal bipyramidal structure, there are five positions for the atoms around the central atom. Three of these positions form an equatorial plane in the shape of an equilateral triangle, while the remaining two positions are above (apical) and below (apical) the central atom.
02

Examine the First Compound: \(\mathrm{CH}_{3} \mathrm{PF}_{4}\)

In this compound, there is one methyl group and four fluorine atoms bound to the central phosphorus atom. Since fluorine is more electronegative than carbon, the four fluorine atoms will prefer the apical positions and the single methyl group will be placed in the equatorial position. Thus, there is only one kind of methyl and one kind of fluorine environment in this molecule.
03

Examine the Second Compound: \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{PF}_{3}\)

In this compound, there are two methyl groups and three fluorine atoms bound to the central phosphorus atom. One fluorine atom will occupy an apical position, while the other two fluorine atoms will be in equatorial positions due to the limited availability of apical positions. The two different fluorine environments are in the ratio of 2:1, representing two equatorial and one apical fluorine atom. The methyl groups will occupy the remaining two equatorial positions, resulting in one kind of methyl environment.
04

Examine the Third Compound: \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{PF}_{2}\)

In this compound, there are three methyl groups and two fluorine atoms bound to the central phosphorus atom. The two fluorine atoms will occupy the apical positions. The three methyl groups will occupy the remaining equatorial positions, which are symmetry-equivalent, resulting in one kind of methyl environment. The two kinds of fluorine in this molecule refer to the two distinct apical positions. In conclusion, the given nuclear magnetic resonance data can be explained by considering the trigonal bipyramidal structures of these pentacovalent phosphorus compounds and the preferences of the more electronegative substituents for the apical positions.

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