When methyl \(\alpha-\mathrm{D}-\) glucoside was treated with \(\mathrm{HIO}_{4}\), it yielded 1 mole of formic acid, plus a product (A). Write the structure of \(\mathrm{A}\). When a methyl glycoside of unknown structure (B) was similarly treated with \(\mathrm{HIO}_{4}\), only 1 mole of \(\mathrm{HIO}_{4}\), was consumed, and no formic acid was produced, but the same product (A) was obtained. Draw the configurational structure of \(\mathrm{B}\).

Short Answer

Expert verified
The structure of product A is: \(CH_3-CH(OH)-CH(OH)-CH(OH)-CH_2OH\), which represents a methyl-glyceraldehyde molecule. The configurational structure of compound B is: \(CH_3-CH(OH)-CH(OH)-CH(OH)-CH_2OH - (--) - O - Sugar\), with the glycosidic bond attached to the anomeric carbon of the sugar moiety. The attached sugar moiety cannot be identified based on the information given.

Step by step solution

01

Analyze Reaction 1 and Infer Structure of A

In Reaction 1, methyl \(\alpha-\mathrm{D}\)-glucoside is treated with \(\mathrm{HIO}_{4}\), yielding 1 mole of formic acid and product A. Given that \(\mathrm{HIO}_4\) is a strong oxidizing agent and breaks C-C bonds, we can infer that the bond adjacent to the anomeric carbon in methyl \(\alpha-\mathrm{D}\)-glucoside is broken, resulting in the formation of formic acid and the remaining part of the molecule, which is product (A). Methyl \(\alpha-\mathrm{D}\)-glucoside is a glucose molecule with a methyl group at the anomeric carbon. The oxidation process breaks the C1-C2 bond, and so the structure of product A is glucose without C1 and C2 attached, forming an aldehyde at C3: Product A: \(\mathrm{CH_3-CH(OH)-CH(OH)-CH(OH)-CH_2OH}\), which represents a methyl-glyceraldehyde molecule.
02

Analyze Reaction 2 and Infer Structure of Unknown Methyl Glycoside (B)

In Reaction 2, an unknown methyl glycoside (B) is treated with \(\mathrm{HIO}_{4}\), consuming 1 mole of \(\mathrm{HIO}_{4}\) without forming any formic acid, but yielding the same product A. This information suggests that the glycoside (B) only has one bond susceptible to oxidation, but that this bond is not connected directly to the anomeric carbon (as no formic acid is produced). Since product A is formed in both reactions, we can infer that compound B also has the same methyl-glyceraldehyde structure as product A. The only difference is that in compound B, there is a glycosidic bond with the anomeric carbon of another sugar moiety. This bond does not break because it is not directly connected to the anomeric carbon. Thus, the structure for the unknown glycoside compound (B) is a disaccharide that has product A as one of its units, with a glycosidic bond with the anomeric carbon of another sugar moiety. Hence, the configurational structure of compound B is: \(\mathrm{CH_3-CH(OH)-CH(OH)-CH(OH)-CH_2OH} - \mathrm{(--) - O - Sugar}\), with the glycosidic bond attached to the anomeric carbon of the sugar moiety. Further identification of the attached sugar moiety would require additional information not provided in this exercise.

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Most popular questions from this chapter

Polysaccharides known as dextrans have been used as substitutes for blood plasma in transfusions; they are made by the action of certain bacteria on (+)-sucrose. Interpret the following properties of a dextran: Complete hydrolysis by acid yields only \(\mathrm{D}-(+)\) -glucose. Partial hydrolysis yields only one disaccharide and only one trisaccharide, which contain only \(\alpha\) -glycoside linkages. Upon methylation and hydrolysis, there is obtained chiefly \(2,3,4\) -tri-O-methyl-D-glucose, together with smaller amounts of 2,4 -di-O-methyl-D-glucose and \(2,3,4,6\) -tetra- O-methyl-D- glocuse.

A disaccharide, \(\mathrm{G}, \mathrm{C}_{11} \mathrm{H}_{20} \mathrm{O}_{10}\), is hydrolyzable by \(\alpha\) glucosidase, yielding D-glucose and a D-pentose. The disaccharide does not reduce Fehling's solution. Methylation of \(\mathrm{G}\) with dimethyl sulfate in NaOH yields a hepta-methyl ether, \(\mathrm{H}\), which upon acid hydrolysis yields \(2,3,4,6\) -tetra-O methyl-D- glucose and a pentose tri-O- methyl ether, (I). Oxidation of I by bromine water yields \(2,3,4\) -tri-O-methyl-D ribonic acid. Assign structures to compounds G through I compatible with these data.

D-Raffinose is a trisaccharide that does not react with Fehling's solution. Upon hydrolysis it produces \(\mathrm{D}\) - glucose, D-galactose, and D-fructose. Completely methylated raffinose is hydrolyzed to \(2,3,4-\) tri- O -methylglucose, \(1,3,4,6-\) tetra-O-methylfrueto se, and \(2,3,4,6-\) tetra- \(\mathrm{O}-\) methylgalactose. What structures for raffinose are consistent with these data? What further information, if any, is required to identify completely the structure of raffinose?

Will 2-deoxyribose form an osazone? Why?

Show how the structure of maltose can be deduced from the following evidence: (a) The sugar is hydrolyzed by yeast \(\alpha\) -D-glucosidase to \(\mathrm{D}\) glucose. (b) Maltose mutarotates and forms a phenylosazone. Methylation with dimethyl sulfate in basic solution followed by acid hydrolysis gives \(2,3,4,6\) -tetra- \(\mathrm{O}\) -methyl-Dglucopyranose and \(2,3,6-\) tri-O-methyl- D-glucose. (c) Bromine oxidation of maltose followed by methylation and hydrolysis gives \(2,3,4,6\) -tetra-O-methyl-D- glucopyranose and a tetramethyl-D-gluconic acid which readily forms a \(\gamma\) -lactone.

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