Write equations for the steps involved in hydrolysis of adenine deoxyribonucleoside to deoxyribose and adenine. Would you expect the reaction to occur more readily in acidic or basic solution?

Short Answer

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The hydrolysis of adenine deoxyribonucleoside (AD) can be represented by the reaction equation: \( AD + H_2O \rightarrow Adenine + Deoxyribose \). This process involves breaking the N-glycosidic bond by introducing a water molecule. The reaction is expected to occur more readily in acidic solutions than in basic ones, as protonation of the nitrogen atoms in the nucleobase under acidic conditions enhances the cleavage of the N-glycosidic bond. In basic solutions, competition between nucleophilic centers and the dissociation of the unshared electron pair in the nitrogen might affect the hydrolysis rate.

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01

Write the reaction equation for the hydrolysis of adenine deoxyribonucleoside to deoxyribose and adenine

The hydrolysis of adenine deoxyribonucleoside (AD) can be written as follows: \[ AD + H_2O \rightarrow Adenine + Deoxyribose \] Adenine deoxyribonucleoside is composed of the nitrogenous base adenine and the sugar deoxyribose linked by an N-glycosidic bond. The reaction consists of breaking the N-glycosidic bond by introducing a water molecule.
02

Discuss the effect of acidic and basic solutions on the reaction

When it comes to hydrolysis reactions, the presence of acidic or basic solutions can affect their rate and mechanism. In acidic solution, protonation might occur in the nucleobase, making the glycosidic bond more susceptible to cleavage, leading to the formation of the adenine and deoxyribose. The reaction can be written as: \[ AD + H^+ + H_2O \rightarrow Adenine + Deoxyribose + H^+ \] In a basic solution, the hydroxide ion (OH-) attacks the electrophilic center of the glycosidic bond and makes it more prone to breakage. The reaction can be written as: \[ AD + OH^- \rightarrow Adenine + Deoxyribose + OH^- \] Considering the nature of nucleobases and their nucleophilic centers (lone pair electrons in the nitrogen atoms), the hydrolysis of adenine deoxyribonucleoside is expected to occur more readily in acidic than in basic solutions. The protonation of the nitrogen atoms in the nucleobase under acidic conditions enhances the cleavage of the N-glycosidic bond, while in a basic solution, a competition between the nucleophilic centers and the dissociation of the unshared electron pair in the nitrogen might affect the hydrolysis rate.

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Most popular questions from this chapter

(a) What is the difference between a nucleoside and a nucleotide? (b) What would you anticipate to be the difference between a riboside and a ribotide? (c) How would thev be similar?

In DNA, the bases are bonded to deoxyribose at the following positions (that is a hydrogen in the Figure below is replaced by \(\mathrm{C}-1\) of the sugar); adenine and guanine, \(\mathrm{NH}\) in the five-membered ring; cytosine and thymine, the lower NH. (a) Draw the structures to show likely hydrogen bonding between adenine and thymine; between guanine and cytosine, (b) Can you account for the fact that guanine and cytosine pairs hold the chains together more strongly than do adenine and thymine pairs?

Outline a synthesis for adenine, one of the purines, from hydrogen cyanide and ammonia.

Escherichia coli bacteria grown in a medium containing \({ }^{15}\) N-labeled ammonium chloride produce \({ }^{15} \mathrm{~N}\) -containing DNA. This can be distinguished from ordinary \({ }^{14} \mathrm{~N}-\mathrm{DNA}\) by ultracentrifugation in concentrated cesium chloride solutionthe heavier \({ }^{15}\) N-labeled DNA undergoing sedimentation more rapidly. When the bacteria grown in an \({ }^{15} \mathrm{~N}\) medium are transferred to an \({ }^{14} \mathrm{~N}\) medium, DNA replication continues but, after one generation, all the DNA present appears to be of one kind, containing equal amounts of \({ }^{15} \mathrm{~N}\) and \({ }^{14} \mathrm{~N}\); after two generations, the DNA is now of two kinds present in equal amounts \(-\) all \({ }^{14} \mathrm{~N}-\mathrm{DNA}\) and \({ }^{14} \mathrm{~N},{ }^{15} \mathrm{~N}-\mathrm{DNA}\). What do these results tell about the replication of DNA and its stability in the cell?

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