Describe dehalogenation of vicinal dihalides to obtain an alkene.

Short Answer

Expert verified
Dehalogenation of vicinal dihalides involves converting a compound with two halogen atoms on adjacent carbon atoms into an alkene by removing the halogen atoms and forming a double bond between the carbons. This process typically uses zinc as a reducing agent, resulting in the following reaction: \(RCHX-CHXR' + Zn \rightarrow RCH=CHR' + ZnX_2\). The final product is an alkene, which is a valuable and versatile compound in organic chemistry.

Step by step solution

01

Identify the vicinal dihalide

A vicinal dihalide is a compound with two halogen atoms bonded to two neighboring (vicinal) carbon atoms. A general example of a vicinal dihalide is given below: \[RCHX-CHXR'\] where R and R' represent alkyl groups, and X represents halogen atoms.
02

Choose a suitable dehalogenating agent

In order to carry out the dehalogenation, we need to find a suitable reducing agent. Common reducing agents used for this purpose are zinc (Zn) and a strong base. For this explanation, we will use zinc as the reducing agent.
03

Perform the dehalogenation

To perform the dehalogenation, the vicinal dihalide is treated with the reducing agent. Reacting the vicinal dihalide with zinc in the presence of an alcohol solvent (e.g., ethanol) will result in the removal of both halogen atoms (X) and the formation of a new double bond between the two carbon atoms. The overall balanced equation for the reaction can be represented as: \[RCHX-CHXR' + Zn \rightarrow RCH=CHR' + ZnX_2\]
04

Identify the alkene product

The product of dehalogenation is an alkene with a double bond between the two carbon atoms that were originally bonded to the halogen atoms. In our general example, the product would be: \[RCH=CHR'\] Dehalogenation of vicinal dihalides provides an efficient synthetic route to produce alkenes from readily available starting materials.

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