Which compound in each pair forms the higher percentage of gem-diol at equilibrium?

a.

or

b.

or

Short Answer

Expert verified

a.

b.

Step by step solution

01

Hydrate formation

Carbonyl compounds would undergo hydration to form diols. The thermodynamic stability of the hydrate would depend on the nature of substituents on the carbonyl carbon.

02

 Comparison of given compounds  

Consider the given pair of organic compounds,

a. Among the given compounds, butanal would form the higher percentage of gem-diols at equilibrium than but-2-one.

This occurs because alkyl group being electron-releasing group (ERG) would stabilize the carbonyl compound shifting the equilibrium backward.

Given pair a.

b. Among the given compounds, 2,2-difluropropanal would form the higher percentage of gem-diols at equilibrium than propan-1-al.

This occurs because halides being an electron-withdrawing group (EWG) would destabilize the carbonyl compound shifting the equilibrium forward.

The presence of fluoride ions would develop a partial positive charge on the alpha-carbon, which would destabilize the carbonyl carbon.

Given pair b.

03

Stable carbonyl compound

The carbonyl compound that would give a higher percentage of gem-diol is as follows:

a.

Compound that forms the higher percentage of gem-diol at equilibrium in pair a.

Compound that forms the higher percentage of gem-diol at equilibrium in pair b.

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Most popular questions from this chapter

A solution of acetone (CH3)2C=O in ethanol CH3CH2OH in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm-1 , and the 1H-NMR spectrum is given here. What is the structure of the product?

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