Chapter 31: Question 31.4 (page 1237)

The main fatty acid component of the triacylglycerols in coconut oil is lauric acid,CH3(CH2)10COOH . Explain why coconut oil is a liquid at room temperature even though it contains a large fraction of this saturated fatty acid.

Short Answer

Expert verified

Answer

Coconut oil is composed of both saturated and unsaturated fatty acids. Hence it can exist in its liquid form at room temperature.

Step by step solution

01

Fatty acids

There are numerous kinds of fatty acids, and one among them issaturated fatty acid.These acids do not comprise a carbon-carbon double bond. An example of a saturated fatty acid is lauric acid.

02

Lauric acid

Another name for lauric acid is dodecanoic acid. It comprises several salts and esters referred to as laurates. It is a part of triglycerides, and fifty percent of fatty-acid content in oils like coconut oil and laurel oil is due to lauric acid.

03

Reason for coconut oil to be a liquid at room temperature

Coconut oil comprises of 86% saturated fatty acid and 7% oleic acid.

The saturated fatty acid is a part of the triacylglycerol, lauric acid. The condensed formula of lauric acid is CH3CH210COOH. The structure of lauric acid can be given as:

Structure of lauric acid

It comprises of 12 carbon atoms with no double bonds. The melting point of lauric acid is44°C.

The condensed formula of oleic acid isCH3CH27CH=CHCH27COOH. It is an unsaturated fatty acid comprising of 18 carbon atoms with no double bond. The melting point of oleic acid is4°C.

Since coconut oil comprises saturated and unsaturated fatty acids, it is usually at its liquid form at room temperature.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How would you expect the melting point of eicosapentaenoic acid [CH3CH2CH=CHCH25CH22COOH]to compare with the melting points of the fatty acids listed in Table 31.2?

One component of jojoba oil is a wax formed from eicosenoic acid [CH3CH27CH=CHCH29CO2H]andCH3(CH2)7CH=CH(CH2)8OH . Draw the structure of the wax, including the cis geometry of both carbon-carbon double bonds.

(a) Draw a skeletal structure of the anabolic steroid 4-androstene-3, 17-dione, also called “andro,” from the following description. Andro contains the tetracyclic steroid with carbonyl groups at C3 and C17, a double bond between C4 and C5, and methyl groups bonded to C10 and C13.

(b) Add wedges and dashed wedges for all stereogenic centers with the following information: the configuration at C10 is R, the configuration at C13 is S, and all substituents at ring fusions are trans to each other.

(a) Draw a skeletal structure of the anabolic steroid methenolone from the following description. Methenolone contains the tetracyclic steroid skeleton with a carbonyl group at C3, a hydroxyl group at C17, a double bond between C1 and C2, and methyl groups bonded to C1, C10 and C13. (b) Add wedges and dashed wedges for all stereogenic centers with the following information: The configuration at C10 is R, The configuration at C13 is S, the configuration at C17 is S, and all substitutents at ring fusions are trans to each other. (c) Draw the structures of Primobolan, the product formed when methenolone is treated with CH3(CH2)5COCl and pyridine. Primobolan is an anabolic steroid that can be taken orally or by injection and has been used illegally by well-known Major League Baseball players.

An isoprene unit can be thought of as having a head and a tail. The “head” of the isoprene unit is located at the end of the chain nearest the branch point, and the “tail” is located at the end of the carbon chain farthest from the branch point. Most isoprene units are connected together in a “head-to-tail” fashion, as illustrated. For both lycopene (Problem 31.26), and squalene (Figure 31.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free