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Chapter 18: 24 P (page 708)

Draw the products of each reaction.

Short Answer

Expert verified

Step by step solution

01

Addition elimination reaction

The additionelimination process substitutes nucleophiles by stabilizing the carbanion. The nucleophile is added to the substrate, and then the leaving group is eliminated.

02

Reactivity of the compound

The reactivity of the substrate increases in the presence of an electron-withdrawing group and a highly electronegative atom.

03

Explanation

a. The substrate has two nitro groups, so the methoxy group quickly attacks the carbon at the C-Cl bond.

b. The substrate has the most electronegative group. Therefore, the hydroxide group quickly attacks the carbon at the C-F bond.

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Most popular questions from this chapter

Which of the following compounds undergo Friedel–Crafts alkylation with ${CH}_{3} Cl$ and ${AlCl}_{3}$ ? Draw the products formed when a reaction occurs.

Draw a stepwise mechanism for the following reaction.

Classify each substituent as electron donating or electron withdrawing.

Why is benzene less reactive toward electrophiles than an alkene, even though it has more π electrons than an alkene (six versus two)?

Question: Compound X (molecular formula $C_{10} H_{12} O$ ) was treated with, ${NH}_{2} {NH}_{2}$ , $^{-} OH$ to yield compound Y (molecular formula $C_{10} H_{14}$ ). Based on the $^{1} H$ NMR spectra of X and Y were given below, what are the structures of X and Y?

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