Draw the products formed from the acid-base reaction of HCl with each compound.

a.

b.

c.

d.

Short Answer

Expert verified

a.

b.

c.

d.

Step by step solution

01

Acid-base reaction

Acid-base reactions involve an acid and a base that combine to form species like conjugate acids and conjugate bases.

02

Reaction of compound a

2-Hexanol is a base. It receives a proton from hydrochloric acid and forms a conjugate acid. Hydrochloric acid gives its proton, leading to the formation of a conjugate base.

The reaction is shown as follows:

The reaction of compound a

03

Reaction of compound b

Diethyl ether serves as a base. It receives a proton from hydrochloric acid to form a conjugate acid. Hydrochloric acid donates a proton, leading to the formation of a conjugate base.

The reaction is shown as follows:

The reaction of compound b

04

Reaction of compound c

Tertiary amine acts as abase. It takes hydrogen from hydrochloric acid to form a conjugate acid. Hydrochloric acid gives a proton, leading to the formation of a conjugate base.

The reaction taking place is shown as follows:

The reaction of compound c

05

Reaction of compound d

Secondary amine acts as a base. It acquires a proton from hydrochloric acid to form a conjugate acid. Hydrochloric acid gives its proton, leading to the formation of a conjugate base.

The reaction taking place is shown as follows:

The reaction of compound d

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