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Chapter 10: Q.15. (page 401)

Question: Draw the products formed when each alkene is treated with HCl.

Short Answer

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Answer

Step by step solution

01

Addition of HX to an alkene

The HX molecule adds to the double bond in the alkene and leads to the formation of a single bond.

02

Markovnikov’s rule

The hydrogen atom adds to that carbon from the bond which has more hydrogen atoms bonded to it.

03

Products of the given reactions

a. The product of the given reaction is provided hereunder.

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Most popular questions from this chapter

Question: Draw a stepwise mechanism for the following reaction, which results in ring expansion of a six-membered ring to a seven-membered ring.

Question: Addition of HBr to which of the following alkenes will lead to a rearrangement?

Question: Give the structure corresponding to each name.

a. (E)-4-ethylhept-3-ene

b. 3,3-dimethylcyclopentene

c. 4-vinylcyclopentene

d. (Z)-3-isopropylhept-2-ene

e. cis-3,4-dimethylcyclopentene

f. 1-isopropyl-4-propylcyclohexene

g. 3,4-dimethylcyclohex-2-enol

h. 3,5-diethylhex-5-en-3-ol

Question: Draw the structure corresponding to each IUPAC name.

a. (Z)-4-ethylhept-3-ene

b. (E)-3,5,6-trimethyloct-2-ene

c. (Z)-2-bromo-1-iodohex-1-ene

Question: a. Which diastereomer of oct-4-ene yields a mixture of two enantiomers, (4R,5R)- and (4S,5S)-4,5-dibromooctane on reaction with Br2 ?

b. Which diastereomer of oct-4-ene yields a single meso compound, (4R,5S)-4,5-dibromooctane?
See all solutions

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