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Chapter 10: Q.24. (page 407)

Question: Draw all stereoisomers formed in each reaction.

Short Answer

Expert verified

Answer

c.

Step by step solution

01

Step 1:Reaction of an alkene with a dihalide

The reaction involves the anti-addition of halogen to the double bond. Enantiomers are formed during this reaction.

02

Formation of products for a, b and c

a. The reaction of 1-methylcyclopent-1-ene with dichloride is shown below:

Product formation in a

b. The reaction of (S)-3-methylcyclohex-1-ene with dichloride is shown below:

Product formation in b

c. The reaction of (E)-1,2-diphenylethene with dichloride is shown below:

Product formation in c

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Most popular questions from this chapter

Question: Explain why the addition of HBr to alkenes A and C is regioselective, forming addition products B and D, respectively.

Question: What alkene can be used to prepare each alcohol as the exclusive product of a two-step hydroboration–oxidation sequence?

Question: Draw the products formed when each alkene is treated with HCl.

Question: Label each carbon-carbon double bond in 11-cis-retinal as E or Z. As we will learn in Section 21.11, the isomerization of one double bond in this compound to a less crowded stereoisomer takes place when light strikes the retina of the eye.

Question: Give the IUPAC name for each compound.

a.

b.

c.

d.

e.

f.
See all solutions

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