Question: For each reaction, use the identity of the alkyl halide and nucleophile to determine which substitution mechanism occurs. Then determine which solvent affords the faster reaction

a.

b.

c.

Short Answer

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Answer

  1. The substrate and the nucleophile favor the SN1 mechanism. CH3OH is a polar protic solvent. It enhances the rate of the SN1 mechanism.
  2. The substrate and the nucleophile favor SN2 the mechanism. DMF is a polar aprotic solution, and it enhances the rate of the SN2 mechanism.
  3. The substrate favors the SN1 mechanism, and the nucleophile favors the SN2 mechanism. The solvent HMPA is a polar aprotic solution, so it enhances the rate of SN2 the reaction.

Step by step solution

01

SN1 reactions

This is a two-step reaction.

In these reactions, the leaving group leaves first and hence forming a carbocation. The carbocation is then attacked by the nucleophile.

The rate of the reaction depends upon the leaving group and the nature of the nucleophile.

The polar protic solvents enhance the rate of the SN1 mechanism.

A weak nucleophile favors SN1 mechanism.

02

SN2 reactions

These reactions do not involve the formation of the carbocation.

In this reaction, one bond is broken, and another bond is formed simultaneously.

A strong nucleophile favors the SN2 mechanism. The polar aprotic solutions enhance the rate of the SN2 mechanism.

03

Determination of the reaction pathway

a. (CH3CH2)2C(CH3)Cl is a tertiary substrate, so it favorsSN1 the mechanism. CH3OH is a weak nucleophile; hence, it favors SN1 mechanism.

Since CH3OH is a polar protic solvent, it enhances the rate of the SN1 mechanism.

b. CH3CH2Br is a primary substrate, so it favors the SN2 mechanism.-OH is a strong nucleophile; hence, it favors SN2 mechanism.

Since DMF is a polar aprotic solution, it enhances the rate of the SN2 mechanism.

c. (CH3CH2)2CCl is a secondary substrate, so it favors SN1 the mechanism.

However, since CH3O-is a strong nucleophile, it favors the SN1 mechanism. The solvent HMPA is a polar aprotic solution, so it enhances the rate of the SN2 reaction.

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Most popular questions from this chapter

Question: You will often return to nucleophilic substitution, in particular the SN2 reaction, in subsequent chapters and concentrate on the nucleophile rather than the alkyl halide. By using different nucleophiles, nucleophilic substitution allows the synthesis of a wide variety of organic compounds with many different functional groups. With this in mind, draw the products of each two-step sequence. (Hint: Step [1] in each part involves an acid-base reaction that removes the most acidic hydrogen from the starting material.)

a.

b.

c.

Question: Uridine monophosphate (UMP) is one of the four nucleotides that compose RNA, the nucleic acid that translates the genetic information of DNA into proteins needed by cells for proper function and development. A key step in the synthesis of UMP is the reaction of A with B to form C, which is then converted to UMP in one step. Draw a stepwise mechanism for this SN1 reaction.

Question: When trichloride J is treated with CH3OH , nucleophilic substitution forms the dihalide K. Draw a mechanism for this reaction and explain why one Cl is much more reactive than the other two Cl’s so that a single substitution product is formed.

Question: Consider the following SN1 reaction.

  1. Draw a mechanism for this reaction using curved arrows.
  2. Draw an energy diagram. Label the axes, starting material, product Eaand H°. Assume that the starting material and product are equal in energy.
  3. Draw the structure of any transition states.
  4. What is the rate equation for this reaction?
  5. What happens to the reaction rate in each of the following instances? [1] The leaving group is changed from I- to Cl-;[2] The solvent is changed from H2O to DMF; [3] The alkyl halide is changed from (CH3)2 C(I) CH2CH3 to (CH3) CHCH(I)CH3 ; [4] The concentration of H2O is increased by a factor of five; and [5] The concentrations of both the alkyl halide and H2O are increased by factor of five.

Question: Which compound in each pair has the higher boiling point?

a.

b.

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