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Chapter 29: Question 30.30 (page 1152)

Draw each polymer in Problem 30.29 using the shorthand representation shown in Figure 30.2.

Short Answer

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Answer

Step by step solution

01

Polymer

Polymers are formed by the addition/condensation of monomer units that form large/long-chain molecules.Polymers are also said to be macromolecules i.e. higher molecular mass.

02

Structure of polymer

In the above question, there are 4 polymers in chain form. We have to represent them in shorthand form.

The monomer of this polymer is ethyl acetoacetate.

Structure of ethyl acetoacetate polymer

The monomer of this polymer is amino cyclohexane carboxylic acid.

Structure of amino cyclohexane carboxylic acid polymer

The monomer of this polymer is 2, 2-dimethyl butane carboxyl.

Structure of 2, 2-dimethyl butane carboxyl polymer

The monomer of this polymer is 1, 3-propandiol.

Structure of 1, 3-propandiol polymer

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Most popular questions from this chapter

Write out the steps for the synthesis of each peptide using the Merrifield method:

(a)Ala-Leu-Phe-Phe;

(b) Phe-Gly-Ala-Ile.

Question: For the tetra peptide Asp–Arg–Val–Tyr:

a. Name the peptide using one-letter abbreviations.

b. Draw the structure.

c. Label all amide bonds.

d. Label the N-terminal and C-terminal amino acids

Devise a synthesis of the following dipeptide from amino acid starting materials.

Name each peptide using both the three-letter and one-letter abbreviations of the component amino acids.

Draw the organic products formed in each reaction.

a.

b.
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