Question: Which of the following heterocycles are aromatic?

Short Answer

Expert verified

Answer

  1. This compound has 6πelectrons and is aromatic in nature.
  2. This compound has a total of 6πelectrons and is aromatic in nature.
  3. This compound has a total of 8πelectrons and is, therefore non-aromatic in nature.
  4. This compound has 10π electrons and is aromatic in nature.
  5. This compound is non-aromatic in nature because it has 4π electrons.
  6. This compound has 6πelectrons and is aromatic in nature.
  7. This compound is aromatic in nature because it has 6πelectrons.
  8. This compound has a total of 10πelectrons and is aromatic in nature.

Step by step solution

01

Aromatic compounds

The compounds which are cyclic in nature are planar, conjugated with 4n+2πelectrons, and aromatic in nature.

The aromatic compounds are highly stable. The heterocyclic compounds which have oxygen, nitrogen, sulfur, and a lone pair of electrons are aromatic in nature. The lone pair of electrons on the hetero atom may or may not be a part of the delocalized system.

02

The aromatic compounds among the following heterocyclic compounds

The given heterocyclic compounds can be classified as aromatic compounds if the ring has 4n+2πelectrons. The lone pair of electrons on an atom that is already a part of the multiple bonds cannot be delocalized on the ring. Therefore, such a lone pair of electrons cannot be counted in determining the aromaticity of the ring.


a. This molecule has six pi electrons. The lone pair of electrons from sulfur is also included to calculate the total number of pi electrons. Therefore, the given compound is aromatic in nature.

b. The given compound has a total of six pi electrons which includes a lone pair from the oxygen atom. Therefore, this compound is also aromatic in nature.

c. This compound had a total of eight pi electrons and is, therefore, not aromatic in nature.

d. This compound has ten pi electrons and is aromatic in nature.

e. This compound is non-aromatic in nature because it has four pi electrons.

f. This compound has six pi electrons after including a lone pair of electrons from the oxygen atom. This makes this given compound aromatic in nature.


g. This compound has six pi electrons including the lone pair of electrons from the nitrogen atom. Therefore, this compound is aromatic in nature.

h. This compound has total ten pi electrons including the one from the nitrogen atom which is singly bonded. The lone pair of electrons of nitrogen atoms which are forming a double bond, are not included in the total number of pi electrons.

Therefore, this compound is aromatic in nature.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Which compound in each pair is the stronger acid?

Question: (R)-Carvone, the major component of the oil of spearmint, undergoes acid-catalyzed isomerization to carvacrol, a major component of the oil of thyme. Draw a stepwise mechanism and explain why this isomerization occurs.

Question: Early structural studies on benzene had to explain the following experimental evidence. When benzene was treated with Br2(plus a Lewis acid), a single substitution product of molecular formula C6H5Brwas formed. When this product was treated with another equivalent of Br2, three different compounds of molecular formularole="math" localid="1648727281591" C6H4Br2 were formed.

  1. Explain why a single Kekule structure is consistent with the first result, but does not explain the second result.
  2. Then explain why a resonance description of benzene is consistent with the results of both reactions.

Question: Classify each compound as aromatic, antiaromatic, or not aromatic.

Question: Use the inscribed polygon method to show the pattern of molecular orbitals in cyclooctatetraene.

a. Label the MOs as bonding, antibonding, or nonbonding.

b. Indicate the arrangement of electrons in these orbitals for cyclooctatetraene, and explain why cyclooctatetraene is not aromatic.

c. Treatment of cyclooctatetraene with potassium forms a dianion. How manyπelectrons does this dianion contain?

d. How are the πelectrons in this dianion arranged in the molecular orbitals?

e. Classify the dianion of cyclooctatetraene as aromatic, antiaromatic, or not aromatic, and explain why this is so.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free