What product is formed when each alkene is treated with and Zn(Cu)?

a.

b.

c.

Short Answer

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Answer

a.

b.

c.

Step by step solution

01

Alkene

Compounds consisting of double-bonds are designated as alkenes. Alkenes can be categorized into monosubstituted, disubstituted, etc., based on the count of alkyl groups connected to the carbon atom.

02

Simmons–Smith reaction

Alkenes combine with diiodomethane and the zinc reagent Zn(Cu) to create non-halogenated cyclopropanes. This reaction does not require a free carbene.

03

Treatment of the given alkenes with CH2I2 and Zn(Cu)

a.The given alkene reacts with CH2I2 and Zn(Cu) to form a non-halogenated cyclopropane. The reaction of alkene a with CH2I2 and Zn(Cu) can be given as:

Reaction of alkene a with CH2I2 and Zn(Cu)

b. The double bond of cyclopentene converts to a single bond on the reaction with CH2I2 and Zn(Cu). The reaction of alkene b with CH2I2 and Zn(Cu) can be given as:

Reaction of alkene b with CH2I2 and Zn(Cu)

c. The given alkene combines with CH2I2 and Zn(Cu) to produce a product comprising cyclopropane. The reaction of alkene c with CH2I2and Zn(Cu) can be given as:

Reaction of alkene c with CH2I2and Zn(Cu)

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a.

b.

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