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Chapter 24: Q.8. (page 962)

Question: Draw the products formed in the crossed aldol reaction of phenylacetaldehyde $(C_{6} H_{5} C H_{2} C H O)$ with each compound: (a) $C H_{2} {(C O O E t)}_{2}$ ; (b) $C H_{2} {(C O C H_{3})}_{2}$ ; (c) $C H_{3} C O C H_{2} C N$ .

Short Answer

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Answer

a.

b.

c.

Step by step solution

01

Crossed aldol reaction

Aldol reaction carried out using two different (non-identical) carbonyl compounds is referred to as the crossed aldol reaction.

02

Crossed aldol reaction mechanism

A crossed-aldol reaction is shown below.

Crossed aldol reaction

03

Products formed in a crossed aldol reaction

a. The reaction of $C_{6} H_{5} C H_{2} C H O$ with $C H_{2} {(C O O E t)}_{2}$ is represented below:

Reaction of phenyl acetaldehyde with $C H_{2} {(C O O E t)}_{2}$

b. The reaction of $C_{6} H_{5} C H_{2} C H O$ with $C H_{2} {(C O C H_{3})}_{2}$ is represented below:

Reaction of phenyl acetaldehyde with $C H_{2} {(C O C H_{3})}_{2}$

c. The reaction of $C_{6} H_{5} C H_{2} C H O$ with $C H_{3} C O C H_{2} C N$ is represented below:

Reaction of phenyl acetaldehyde with $C H_{3} C O C H_{2} C N$

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Most popular questions from this chapter

Question: What cyclic product is formed when each 1,5-dicarbonyl compound is treated with aqueous $O H$ ?

Question: Following the two-step reaction sequence depicted in Figure 24.5, write out the steps needed to convert A to B.

Question: Draw the product formed in each directed aldol reaction.

Question:Draw the product formed from a Michael reaction with the given starting materials using $O E t, E t O H$ .

Question: Fill in the lettered reagents needed for each reaction.

See all solutions

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