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Chapter 3: Q.59. (page 91)

Question: Which compound is more likely to be a general anesthetic? Explain your choice.

Short Answer

Expert verified

Answer

Compound B.

Step by step solution

01

Characteristics of anesthetics

Low solubility in the bloodstream
Reversibility
Memory loss of pain

The compounds with low polarity, no hydrogen bonding, and non-polar nature are good for general anesthetics.

02

Explanation

The given compound A has fluoride and oxygen groups, which form hydrogen bonds with the water molecule in the body. Therefore, the solubility of the compound is high.

Thus, it affects the body more. Hence, compound A is not preferred for general anesthetics.

The given compound B is in zwitterion form (neutral form). Therefore, the solubility of the compound is low. The body can quickly be in an active mode. Hence, compound B is better for general anesthetic.

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Most popular questions from this chapter

Question:a. Classify the carbon atoms in each compound as $1^{0}$ , $2^{0}$ , $3^{0}$ , or $4^{0}$ . b. Classify the hydrogen atoms in each compound as $1^{0}$ , $2^{0}$ , $3^{0}$ .

$[1]$

$[2]$

$[3]$

$[4]$

Question: What reaction occurs when is treated with a. $H_{2} S O_{4}$ ? b. NaH? What happens when is treated with these same reagents?

Question: Label the electrophilic and nucleophilic sites in each molecule.

a.

b.

c.

d.

Question: Predict the water solubility of each of the following organic molecules.

a.

b.

c.

d.

Question: Rank the following compounds in order of increasing water solubility.

See all solutions

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