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Chapter 14: Q.21558-14-19P. (page 551)

Draw a splitting diagram for Hb in trans-1,3-dichloropropene, given that Jab = 13.1 Hz and Jbc = 7.2 Hz.

Short Answer

Expert verified

Spin-spin coupling is the interaction of proton spins through the mediating bonding electrons. The bonding electron pairs its spin with the spin of the nearest proton.

Step by step solution

01

Spin-spin coupling

Spin-spin coupling is the interaction of proton spins through the mediating bonding electrons. The bonding electron pairs its spin with the spin of the nearest proton.

02

Coupling constant (J)

The distance between the peaks in a multiplet is called the coupling constant. The coupling constant is a measure of how strongly a nucleus is affected by the spin states of its neighbor. Its magnetic field is independent of applied field strength.

03

Drawing a splitting diagram for Hb.

Structure of trans-1, 3-dichloroprene

1 trans Ha proton splits the Hb into 1 + 1 = 2 peaks, so it will get a doublet. 2 Hc protons split Hb into 2 + 1 = 3 peaks, then a doublet of triplets is obtained. Therefore, the splitting diagram for Hb can be drawn as:

Splitting diagram for Hb

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Most popular questions from this chapter

Rank the highlighted carbon atoms in each compound in order of increasing chemical shift.

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Question: Using a 300 MHz NMR instrument:

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Question: Identify the structures of isomers A and B (molecular formula C9H10O ).

Compound A: IR peak at 1742 cm-1 ; 1 H NMR data (ppm) at 2.15 (singlet, 3 H), 3.70 (singlet, 2 H), and 7.20 cm-1(broad singlet, 5 H). Compound B: IR peak at 1688 ; 1 H NMR data (ppm) at 1.22 (triplet, 3 H), 2.98 (quartet, 2 H), and 7.28–7.95 (multiplet, 5 H).
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