Spectroscopic data is used to identify unknown compounds.

The data can be used to interpret the structure and bonding of the compound.

It is given that the compound shows an IR absorption at 3600 to 3200 cm^-1.

An IR absorption at 3600 to 3200 cm^-1corresponds to a hydroxyl (-OH) group.

Hence, it is identified that the given compound is an alcohol.

In the given spectrum, the single peak (singlet) at 2.4 ppm corresponds to the OH group.

The peak (doublet) at 1.2 ppm corresponding to 6H indicates that the compound consists of six equivalent hydrogen atoms (i.e., the hydrogen atoms with the same chemical environment).

The peak at 1.2 ppm corresponds to alkyl hydrogens.

Since it is given that six hydrogens give a doublet, the carbon atom adjacent to the carbon to which the desired hydrogen is bonded consists of only one hydrogen.

According to the n+1 rule, the multiplicity of a peak depends on the hydrogen atoms present adjacent to it.

n represents the number of hydrogen atoms attached to the carbon adjacent to the concerned proton/hydrogen.

Therefore, it can be assumed that two CH₃ groups are attached to a CH group.

The arrangement of methyl groups in the given compound

This is in accordance with the peak (multiplet) at 3.9 ppm corresponding to 1H.

The multiplicity of the peak corresponding to the CH group, according to the n+1 rule, is:

$$\begin{gathered} \mathrm{n}+1=6+1 \\ =7\left(\mathrm{multiplet}\right) \end{gathered}$$

The chemical shift of 3.9 ppm indicates that the CH group is directly attached to an electron-withdrawing atom/group.

On combining all points, the structure of the given compound is:

Structure of the given compound