Chapter 14: Q.21558-14-27P. (page 557)
How many lines are observed in the 13C NMR spectrum of each compound?
a.
b.
c.
d.
Short Answer
a. Two lines
b. Four lines
c. Three lines
d. Four lines
Chapter 14: Q.21558-14-27P. (page 557)
How many lines are observed in the 13C NMR spectrum of each compound?
a.
b.
c.
d.
a. Two lines
b. Four lines
c. Three lines
d. Four lines
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Get started for freeQuestion: Rank the highlighted carbon atoms in each compound in order of increasing chemical shift.
a.
b.
Question: How many 13C NMR signals do each compound exhibit?
Question: Reaction of C6H5CH2CH2OH with CH3COCl affords compound W, which has molecular formula C10H12O2. W shows prominent IR absorptions at 3088–2897, 1740, and 1606cm-1 . W exhibits the following signals in its 1 H NMR spectrum: 2.02 (singlet), 2.91 (triplet), 4.25 (triplet), and 7.20–7.35 (multiplet) ppm. What is the structure of W? We will learn about this reaction in Chapter 22.
Draw all constitutional isomers of molecular formula \({{\bf{C}}_{\bf{3}}}{{\bf{H}}_{\bf{6}}}{\bf{C}}{{\bf{l}}_{\bf{2}}}\).
a. How many signals does each isomer exhibit in its \({}^{\bf{1}}{\bf{H}}\) NMR spectrum?
b. How many lines does each isomer exhibit in its \({}^{{\bf{13}}}{\bf{C}}\) NMR spectrum?
c. When only the number of signals in both \({}^{\bf{1}}{\bf{H}}\) and \({}^{{\bf{13}}}{\bf{C}}\) NMR spectroscopy is considered, is it possible to distinguish all of these constitutional isomers?
Question: Label the signals due to Ha ,Hb and Hc in the 1 H NMR spectrum of acrylonitrile (CH2=CHCN ). Draw a splitting diagram for the absorption due to the proton Hc.
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