The NMR spectra is obtained by employing continuous wave method in ¹H NMR. The chemical shift of ¹H NMR ranges from 0 to 14 ppm.

The various types of carbon atoms can be identified with the help of signals produced by the ¹³C NMR spectrum.

The given molecular formula is C₄H₈0₂ . The double bond equivalence (DBE) of the molecule can be found as:

DBE=C+1 -$\frac{H}{2}-\frac{X}{2}+\frac{N}{2}$

Where,

• C denotes the number of carbon atoms,
• H denotes the number of hydrogen atoms,
• X denotes the number of halogen atoms and
• N denotes the number of nitrogen atoms.

The values can be substituted as:

DBE=4+1-$\frac{8}{2}-0+0$

=5-4

=1

The double bond equivalence is one which indicates that the compound contains one double bond or one ring in the compound. It does not exhibit IR peaks at 3600–3200 or which indicates the absence of carbonyl and alcohol group. Hence, the structure of the compound is given as:

Structure of the compound with molecular formula C₄ H₈ 0₂

All the protons and carbon are equivalent for this molecule and it exhibits one singlet at 3.69 ppm for NMR spectrum and one line at 67 ppm is observed for the ¹³C spectrum.