Question: Synthesize each compound from (CH₃)₃ CH.

a.

b.

c.

The disintegration of a covalent bond in which shared electrons are left in every fragment is called homolytic cleavage. When the distribution of electrons is equal in bonds, it is homolytic, or else it will be heterolytic cleavage.

Firstly, the Br₂ reagent will be used which gets homolyticallycleavedin the presence of light and forms two bromine radicals. The reaction is as follows:

Br₂$\underset{}{\to }$2Br

In the presence of bromine radical, the homolytic cleavage of the C-H bond will take place in (CH₃)₃CH and will form free radicals like (CH₃)₃$C*$ and $H*$.

a. The hydrogen attached gets replaced by bromine through the process of bromination in presence of ultraviolet rays.

Synthesis of compound a

b. The bromination step followed by potassium tert-butoxide gives the compound b.

Synthesis of compound b

c. The bromination step followed by aqueous potassium hydroxide as a reagent gives the compound c.

Synthesis of compound c