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Chapter 15: Q17. (page 570)

Question: Draw the products of each reaction.

a.

b.

c.

Short Answer

Expert verified

Answer

a.

b.

c.

Step by step solution

01

Allylic bromination with NBS

The two steps involved in this reaction are; initiation and propagation.

02

Formation of products

a.

The reaction is shown below:

Product formation in a

b.

The reaction is shown below:

Product formation in b

c.

The reaction is shown below:

Product formation in c

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Most popular questions from this chapter

Question:A and B, isomers of molecular formula C3H5Cl3 , are formed by the radical chlorination of a dihalide C of molecular formula C3H6Cl2 .

(a) Identify the structures of A and B from the following NMR data:

Compound A: singlet at 2.23 and singlet at 4.04 ppmCompound B: doublet at 1.69, multiplet at 4.34, and a doublet at 5.85 ppm

(b) What is the structure of C?

Question: Using Mechanism 15.1 as a guide, write the mechanism for the reaction of CH4with Br2 to form CH3 Br and HBr. Classify each step as initiation, propagation, or termination.

Question: Draw the major product formed when each cycloalkane is heated with Br2.

a.

b.

c.

d.

Question: Identify the structure of a minor product formed from the radical chlorination of propane, which has molecular formula C3H6Cl2 and exhibits the given 1H NMR spectrum.

Question: Reaction of (CH3 )3 CH with Cl2 forms two products: (CH3 )2 CHCH2Cl (63%) and (CH3)3 CCl (37%). Why is the major product formed by cleavage of the stronger 1° C-H bond?
See all solutions

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