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Chapter 15: Q19. (page 570)

Question: Draw the structure of the four allylic halides formed when 3-methylcyclohexene undergoes allylic halogenation with NBS + hν.

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Answer

Step by step solution

01

Halogenation

Treatment of compound with the halogen yield substituted product. It involves the presence of light.

02

Formation of products

The reaction of methylcyclohexene with NBS in the presence of light. The reaction is shown below:

Formation of products

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Most popular questions from this chapter

Question: What alkane is needed to make each alkyl halide by radical halogenation?

Question: Five isomeric alkanes (A–E) having the molecular formula C6H14 are each treated with Cl2 + hv to give alkyl halides having molecular formula C6H13Cl . A yields five constitutional isomers. B yields four constitutional isomers. C yields two constitutional isomers. D yields three constitutional isomers, two of which possess stereo-genic centres. E yields three constitutional isomers, only one of which possesses a stereo-genic centre. Identify the structures of A–E.

Question:Draw the products formed in each reaction and include the stereochemistry around any stereogenic centers.

a.

b.

c.

d.

Question: When HBr adds to (CH3)2C=CH2 under radical conditions, two radicals are possible products in the first step of chain propagation. Draw the structure of both radicals and indicate which one is formed. Then draw the preferred product from HBr addition under radical conditions.

Question: Draw a stepwise mechanism for the following reaction.
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